Daniellelovee
  • Daniellelovee
An airplane is flying 22 degrees north of east at a speed of 810 km/h. How fast is it moving to the north?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Daniellelovee
  • Daniellelovee
I got 750 is that right?
Daniellelovee
  • Daniellelovee
@Directrix
Directrix
  • Directrix
>I got 750 is that right? Where is the work for this. I don't know Physics well at all.

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Directrix
  • Directrix
From Phone-A-Friend @Douglas The northern component (Vn) of the velocity is: Vn = V{sin(Θ)} Where V is the magnitude of the Velocity (a.k.a the speed) and Θ is the angle North of East. Vn = 810{sin(22º)} = ?
Directrix
  • Directrix
@mamabama disagrees and offers this: Difficult to explain without a triangle but here: The north component of the planes velocity is 810sin(22) = 303.4 The east component is 810cos(22) = 751.0 So the plane is moving north at 303 km/h
Daniellelovee
  • Daniellelovee
thank you so much and im sorry but my computer froze for like half an hour -.-'
Directrix
  • Directrix
Don't assume that either of these is correct without checking.
Daniellelovee
  • Daniellelovee
yeah but I still believe it has to be 750 :/
anonymous
  • anonymous
\[\huge v_\text{North}=|v| \sin (\theta)\] By triangular orthogonal decomposition.
anonymous
  • anonymous
@Directrix Both answers you posted are the same
Daniellelovee
  • Daniellelovee
not really one is 750 and the other one is 810
anonymous
  • anonymous
@Daniellelovee No His first post: `Vn = 810{sin(22º)} = ?` His second post: `The north component of the planes velocity is 810sin(22) = 303.4. So the plane is moving north at 303 km/h` They are the same since 810sin(22)=303.4
shamim
  • shamim
East component of the plane velocity is=810*cos22=?
shamim
  • shamim
And north component of the plane velocity is=810*sin22=?
shamim
  • shamim
U hv to know perpendicular vector resolving

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