anonymous
  • anonymous
Solve x^2 - 3x = -8 Lemme see if I get this right... x^2 - 3x = -8 (x-1.5)^2 = -8 -1 (x-1.5)^2 = -9 x - 1.5 = +or- sqrt9i x-1.5 = 3sqrt2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
I am horribly wrong. These are my choices. http://prntscr.com/92694d
tkhunny
  • tkhunny
You're very close. Give it another go. x^2 - 3x = -8 x^2 - 3x + (3/2)^2 = -8 + (3/2)^2 (x - (3/2))^2 = -8 + (9/4) = -23/4 x - (3/2) = +/- sqrt(-23)/2 x = (3/2) +/- sqrt(-23)/2 x = (3/2) +/- i*sqrt(23)/2
anonymous
  • anonymous
I don't get what to do.

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anonymous
  • anonymous
And the end of your reply is not an answer choice.
anonymous
  • anonymous
@tk
anonymous
  • anonymous
@tkhunny
anonymous
  • anonymous
@pooja195 @kohai
anonymous
  • anonymous
@Kainui @Hero
tkhunny
  • tkhunny
Your first step needs improvement. You can't just declare it a perfect square, you must make it one. Compare your first step to my fist two steps. Where did you get "-1"?
anonymous
  • anonymous
I got -1.5 by dividing 3x by 2.
tkhunny
  • tkhunny
You had 3 You divided by 2 to get 3/2. (3/2)^2 = 9/4 Where did you get -1?
anonymous
  • anonymous
Oh I had a typo there. I meant -1.5 and I guess I stuck with it by accident.
anonymous
  • anonymous
I wanted to do it to both sides :/
anonymous
  • anonymous
What do I do?
tkhunny
  • tkhunny
It's never negative. You must ADD 9/4 to both sides.
anonymous
  • anonymous
Can ya walk me through the rest? I'm really bad at Algebra II.
anonymous
  • anonymous
Hello?
tkhunny
  • tkhunny
Already did. It's in my first post.
anonymous
  • anonymous
Is it 3 + or - isqrt23/2?
tkhunny
  • tkhunny
(3 + or - isqrt23)/2 or 3/2 + or - isqrt23/2? Take your pick.
tkhunny
  • tkhunny
Learning just a little LaTeX goes a VERY long way. \(x = \dfrac{-3\pm i\sqrt{23}}{2}\) or \(x = \dfrac{3}{2}\pm\dfrac{i\sqrt{23}}{2}\)

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