• anonymous
Planet Quirk. PS3, Part II, 3a. The result I am getting is that dL/dh is always less than or equal to delta L over delta h. The question states I should explain the opposite (i.e. delta L/delta h <= dL/dh). I have calculated dL/dh = h/L, delta L = L(h0+delta h) - L (h0). if I take h0 = 20000 and delta h = 1 I get delta L/delta h = 200.002/1=200.002 and dL/dh = 20001/200.002 = 100.003 Am I getting this wrong?
MIT 18.01 Single Variable Calculus (OCW)
• Stacey Warren - Expert brainly.com
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SOLVED
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