http://prntscr.com/92c6uk

- carlyleukhardt

http://prntscr.com/92c6uk

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- schrodinger

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- carlyleukhardt

What is the solution?

- Vocaloid

start by multiplying both sides by 3

- carlyleukhardt

What are the sides? XD

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## More answers

- Vocaloid

both sides of the equation...

- Vocaloid

you have the left side of the equal sign, which is the n(-2n-2)/3 part
and the right side, which is the 12
now multiply both sides by 3

- carlyleukhardt

12=36. But how do i do the first one?

- Vocaloid

when you multiply the expression by 3, the 3 in the denominator cancels out

- Vocaloid

|dw:1447431724131:dw|

- Vocaloid

|dw:1447431754272:dw|

- Vocaloid

now we set that equal to 36 and solve for n

- Vocaloid

|dw:1447431791768:dw|

- Vocaloid

next, distribute the n on the left side

- carlyleukhardt

Im stuck..!! everything made sense but i don't get the (-2n-2) part.

- Vocaloid

apply the distributive property
A(B-C) = A*B - A*C
n(-2n-2) = ?

- carlyleukhardt

n=0 ????

- Vocaloid

no, I'm not asking you to solve for n, I'm asking you to rewrite the expression

- Vocaloid

n*(-2n) = ?

- carlyleukhardt

-2n= n?????????????????? omg :o IM SO CONFUSED ON WHAT TO DO HERE!!!!

- Vocaloid

just multiply them together...

- anonymous

I may be doing my math wrong, but wouldn't it equal -2n^2?

- carlyleukhardt

I don't know what n is though? So how could i multiply n and that?

- Vocaloid

we can still multiply n by n to get n^2, like duck said

- Vocaloid

(n)*(-2n) = -2n^2

- carlyleukhardt

Ohhhh so it equals -2n^2?

- Vocaloid

we can perform math operations on variables without knowing what the variables are
like, how x + x = 2x

- Vocaloid

yes, (n)*(-2n) = -2n^2
now multiply (-2) and n

- carlyleukhardt

-2*n= n? >_<

- Vocaloid

-2*n is just -2n

- carlyleukhardt

Ohhh. Okay... So that's all?

- Vocaloid

now we keep going
n(-2n-2) = -2n^2-2n after we apply the distributive property

- Vocaloid

|dw:1447432448432:dw|

- Vocaloid

then divide both sides by 2

- carlyleukhardt

36 divided by 2 = 18. So what is the next one i divide?

- Vocaloid

don't forget the left side

- carlyleukhardt

2n?

- anonymous

Just a suggestion... wouldn't you want to square root both sides before dividing?

- Vocaloid

why would I take the square root?

- anonymous

Isolation of the variable n, when you have 2n^2, It'd be easier to square root it in the beginning, while you still have a perfect square..

- Vocaloid

|dw:1447432659297:dw|

- anonymous

I may be wrong, but that's just how I saw that.

- anonymous

Oh yeah, sorry. I forgot we still had -2n in there.

- Vocaloid

|dw:1447432712580:dw|

- Vocaloid

|dw:1447432727342:dw|

- carlyleukhardt

WOULD SOMEONE JUST HELP WITH THE ANSWER ALREADY?????? D:

- Vocaloid

then we just move everything to one side and use the quadratic formula

- Vocaloid

|dw:1447432804982:dw|

- carlyleukhardt

So the answer is n=0?

- Vocaloid

no.

- carlyleukhardt

>__________________________________<

- Vocaloid

after we apply the quadratic formula:

- carlyleukhardt

I guess i will put a random answer because my brain can't handle this type of math ;~;

- carlyleukhardt

Yeah... :/

- Vocaloid

|dw:1447433033274:dw|

- Vocaloid

|dw:1447433104045:dw|

- carlyleukhardt

So n= that?

- Vocaloid

yeah

- carlyleukhardt

Thank you so much :D :D :D

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