anonymous
  • anonymous
What is the equation of a line that passes through (-6, 2) and has a slope of -1/2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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zpupster
  • zpupster
you will need point slope form: \[y-y1=m(x-x1)\] we know our slope=m=-1/2 and x1 = -6 y1 = 2 plug those in
anonymous
  • anonymous
y-2=-1/2(x-6)
anonymous
  • anonymous
Is that the answer?

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zpupster
  • zpupster
not yet we should now put it in slope intercept form \[y=mx+b\] can you do that
anonymous
  • anonymous
So... is it -1/2x-1
zpupster
  • zpupster
also there was a mistake with the sign y-2=-1/2(x-6) should be y-2=-1/2(x-(-6)) y-2 = -1/2(x+6)
anonymous
  • anonymous
so its y=-1/2x+5?
zpupster
  • zpupster
y-2 = -1/2(x+6) distribute the -1/2 y-2 = -1/2x -3 add 2 both sides y=-1/2x-1
zpupster
  • zpupster
here you see our point on the line
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anonymous
  • anonymous
ok
anonymous
  • anonymous
so what would the equation be?
zpupster
  • zpupster
well you can see it above or you can see it on the graph
anonymous
  • anonymous
i have four choices a:y=x/2-2 b:y=-x/2-1 c:y=2x+1 d:y=-2x-1

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