stuck-help
  • stuck-help
A dilation has center(0,0,0). Find the image of the point (-1,-2,0) for the scale factor of 3.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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stuck-help
  • stuck-help
@malcolmmcswain
malcolmmcswain
  • malcolmmcswain
Hold on. I'll be right back.
stuck-help
  • stuck-help
ok

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malcolmmcswain
  • malcolmmcswain
Is this a 3-dimensional plane, or did you make a typo? Just asking, because I don't often see three-dimensional planes used in Euclidean, and so far that's all you've posted... -_-
malcolmmcswain
  • malcolmmcswain
If it is a 3D plane, then a dilation by a factor of 3 would be: \[(x \times 3, y \times 3, z \times 3)\] I believe...
malcolmmcswain
  • malcolmmcswain
@lochana I see you're watching. Do you agree?
lochana
  • lochana
yes. I think so
lochana
  • lochana
but wait
malcolmmcswain
  • malcolmmcswain
A dilation by a factor of n is just all the coordinates multiplied by n, right?
lochana
  • lochana
|dw:1447434891284:dw|
lochana
  • lochana
|dw:1447434963673:dw|
lochana
  • lochana
|dw:1447434992705:dw|
lochana
  • lochana
wouldn't it be like that?
malcolmmcswain
  • malcolmmcswain
So you're saying we don't have to multiply z?
lochana
  • lochana
yes. and don't just multiply x and y by 3 either.
lochana
  • lochana
you need scale up first and then find x and y coordinates. let me show you
anonymous
  • anonymous
help me Point A is located at negative 7 over 10 and point B is located at negative 2 over 10. What is the distance between points A and B?
malcolmmcswain
  • malcolmmcswain
Ok... I think I see what you mean.
lochana
  • lochana
|dw:1447435184112:dw| \[OA = \sqrt{(-2)^2 + (-1)^2} = \sqrt{5}\]
lochana
  • lochana
now multiply OA by 3. which is \[3\sqrt{5}\]
malcolmmcswain
  • malcolmmcswain
Ok, I get it now!
malcolmmcswain
  • malcolmmcswain
3D graphs are confusing...
anonymous
  • anonymous
The total temperature change over 3 days in Gritty City was −6 degrees Celsius. What was the average temperature change each day?
lochana
  • lochana
and yes. if we think about proportionality, you end up getting 3x and 3y:)
lochana
  • lochana
@malcolmmcswain you are correct x and y must be multiplied by 3
malcolmmcswain
  • malcolmmcswain
Yeah, I'm kind of thinking about it more on a cartesian plane.
lochana
  • lochana
answer is (-3, -6, 0)
malcolmmcswain
  • malcolmmcswain
^^^ @stuck-help
lochana
  • lochana
@sisigirl02 you can use \[distance = \sqrt{(x1 - x2)^2 + (y1 - y2)^2}\]
stuck-help
  • stuck-help
sorry i had to go do something

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