anonymous
  • anonymous
Solve the equation, 9^4x-3=27^5x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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imqwerty
  • imqwerty
\[9^4x-3=27^5x\] is this ur ques?
Michele_Laino
  • Michele_Laino
I think it is: \[\Large {9^{\left( {4x - 3} \right)}} = {27^{5x}}\] @imqwerty
imqwerty
  • imqwerty
ah yes :)

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More answers

anonymous
  • anonymous
In the first part, the x-3 is in with the power, and in the second part the x is also in with the power. Yes, Michele_Laino that's right
imqwerty
  • imqwerty
\[9^{4x-3}=27^{5x}\]\[3^{2(4x-3)}=3^{3(5x)}\]when bases are same powers are equal so 2(4x-3)=5x can u get x from here?
anonymous
  • anonymous
So now do you just solve for x?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
Okay.
anonymous
  • anonymous
Does x=2?
Michele_Laino
  • Michele_Laino
hint: we can simplify the equation above like below: \[\Large \begin{gathered} 2\left( {4x - 3} \right) = 3\left( {5x} \right) \hfill \\ 8x - 6 = 15x \hfill \\ \end{gathered} \]
AaronAndyson
  • AaronAndyson
:)
anonymous
  • anonymous
So the answer is -6/7?
Michele_Laino
  • Michele_Laino
correct!
anonymous
  • anonymous
Okay, so question with the hint that you gave me where did you get the 3(5x) from?
anonymous
  • anonymous
Okay, so question with the hint that you gave me where did you get the 3(5x) from?
Michele_Laino
  • Michele_Laino
since I can write this: \[\huge {27^{5x}} = {\left( {{3^3}} \right)^{5x}} = {3^{\left( {3 \cdot 5x} \right)}}\]
anonymous
  • anonymous
Ohh, okay. Got it now. Thanks so much!!
Michele_Laino
  • Michele_Laino
:)

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