help me please!!!!!!!!!!!!!!!!!!!!! OMGGGGGGG!!!! X|

- YumYum247

help me please!!!!!!!!!!!!!!!!!!!!! OMGGGGGGG!!!! X|

- Stacey Warren - Expert brainly.com

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- chestercat

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- YumYum247

@Michele_Laino

- YumYum247

@q12157

- anonymous

Have you learned the equation Q=mcT yet?

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## More answers

- YumYum247

yes yes yes!!! !XD

- anonymous

Do you know what c is?

- YumYum247

heat capacity

- YumYum247

sorry...

- YumYum247

i meant specific heat

- anonymous

so what is the specific heat capacity of water

- YumYum247

the amount of energy it requires to raise the temperature of a 1Kg substance by 1 degreeeeeeeee

- YumYum247

4.2X 10^3J/KgC

- YumYum247

but pleaase answer my question please.........can't i just take 2 Kg of water and turn it into steam or something?!?1/1?!!?!?!?!??!!??!?!?

- anonymous

yesh but you need to know the temperature in which water turns into steam...which is?

- YumYum247

hunnet

- anonymous

you can probably do the rest i believe

- YumYum247

ive done the question for 2 KG and not 8Kg.....

- YumYum247

i just took 2Kg water and turned it into stream...

- YumYum247

Q = mct
Q = 8Kg X 4.2X10^3J/KGC X 100C-25C
Q = 2520J

- YumYum247

i honestly don't know what to do :"(

- YumYum247

ok thats the nergy required to boil 8Kg of water.... whats next?????

- anonymous

Find energy of the water at 25 degrees then find energy at of water at 100 degrees. You then subtract

- YumYum247

yes but that would be for 8Kg of water right???????

- YumYum247

any idea????

- YumYum247

and since there is a change of state i think we need to add another formula.......Q = ml

- anonymous

4.46*10^6J?

- YumYum247

what is that????????????/

- anonymous

i cant really think right now, but the answer is prolly something like this:
Q = mct
Q1=8kg*4.2*10^3*25--->Q2+Q3 where Q2=2*4.2*10^3*100 and Q3=2*2.23*10^6
so therefore energy added=Q2+Q3-Q1
which is equal to Q3 since Q2=Q1
and Q3=4.45*10^6
There is a good chance im wrong but im legit dying i need sleep

- anonymous

and by 4.45 i mean 4.46

- YumYum247

ok but there is a change of state of matter....Q= ml......what about that, your turning water to stream

- anonymous

Q3 is the change of state

- anonymous

if im not mistaken m=2 l=2.23*10^6 J/kg or something

- anonymous

I dont remember

- YumYum247

ok hun thanks....i love you,,,,, muuuuuuhhhaaaa, sweet dreams!! :")

- anonymous

yah night lol

- anonymous

sorry if im wrong tho xD

- YumYum247

i'll figure it out eventually.... LOL

- MrNood

OK - first
you need to raise the temperature of the water from 25 C to 100C.
You were correct above and your calculation was:
Q = 8Kg X 4.2X10^3J/KGC X 100C-25C
Q = 2520J
BUT
now you need to add more energy to convert the water at 100 C to Steam at 100 C
for this you need the 'latent heat (or enthalpy) of vapourisation
and the equation is Q= mL
so there are 2 'lots' of energy required:
first 'specific heat' to raise the temp to 100
then 'latent heat' to turn the water into steam at 100 C
add them together for the answer

- anonymous

Thanks Mr Nood lol!
Turns out i slept 17 consecutive hours... wtf

- YumYum247

imma give you a medal just for that....LOL

- YumYum247

i figured out the question......you don't subtract, you divide by 4....since it's a 8:2 ratio.
i did it both ways, i'm getting the same answer!!!!!!! XD

- YumYum247

and yes that's exactly what Mr.Noob said XD....

- MrNood

I have no idea why you seem fixated on 2kg
or any 8:2 ratio
use the specific heat capacity for 8kg raised 75 K
use the latent heat for 8kg from water at 100 C to steam at 100 C
add them together

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