anonymous
  • anonymous
Math help
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
Can you specify?
anonymous
  • anonymous
How many solutions does the equation have? 6 - a = 1/3(9a - 18) A. one solution B. infinite solutions C. no solution
anonymous
  • anonymous
Let's simplify: 6 - a = 1/3(9a - 18) 6 - a = 1/3 x 9a - 1/3 x 18 6 - a = 3a - 6 Rearrange: 12 = 4a a = 3 One solution A

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anonymous
  • anonymous
I'm confused with what you are doing..it makes no sense to me.
anonymous
  • anonymous
Okay. So the first step is simplifying the equation. We only need to look at the right hand side (1/3(9a - 18)) as the left hand side is already in it's simplest form. The first step to simplify 1/3(9a - 18) is to multiply out the brackets. To do this, the number outside the brackets (1/3) has to be multiplied by each number inside the brackets (9a) and (-18) |dw:1447453323820:dw| Good so far?
anonymous
  • anonymous
I understand it a bit better
anonymous
  • anonymous
For this part anyway
anonymous
  • anonymous
Awesome. So once we have \[(\frac{ 1 }{ 3 }\times9a) + (\frac{ 1 }{ 3 }\times(-18))\] we just have to multiply those together. So 1/3 x 9a = 3a (because a third of 9 is 3) and 1/3 x (-18) = 6 (because a third of eighteen is 6 and a positive times a negative is a negative. Then we add those two answers together. So thats 3a + 6.
anonymous
  • anonymous
Oh! It's starting to make much more sense now!
anonymous
  • anonymous
Great! Now that you've simplified the right hand side, we can put the two halves of this equation back together: 6 - a = 3a - 6 The goal now is to get the a on one side and the numbers on the other. Add a to both sides: 6 - a + a = 3a + a - 6 6 + 0 = 4a - 6 6 = 4a - 6 And add 6 to both sides: 6 + 6 = 4a - 6 + 6 12 = 4a + 0 12 = 4a Finally, divide both sides by 4 12/4 = 4a/4 3 = a So swap round (just because conventionally you should put the a first): a = 3
anonymous
  • anonymous
It seems like a lot to do just to get what A is
anonymous
  • anonymous
As you get more confident you'll be able to simplify some of these steps so there is fewer working. This video https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-solving-equations/cc-8th-equation-solutions/v/number-of-solutions-to-linear-equations also looks like it could be useful, if you're interested (I haven't watched the whole thing so can't personally vouch for it)
anonymous
  • anonymous
I'll watch it. Thank you for helping me!
anonymous
  • anonymous
No problem :)

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