• anonymous
On Pset #9 part II problem 2(b.), their answer is div (g G) = ∂(gM) + ∂(gM) ∂x ∂y = (gxM + gMx) + (gyN + gNy) = = (gxM + gyN) + (gMx + gNy) = G · �g + g div(G). Yet why is div(gG) not (gxxM + gxMx) + (gyyN + gyNy) ? since g= why is the partial of g with respect to either variable not gxx or gyy ?
OCW Scholar - Multivariable Calculus
• Stacey Warren - Expert brainly.com
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SOLVED
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