Will someone please help me! I have been stuck on this question for a very long time. The number of diagonals from one vertex in any polygon is 3 less than the number of sides of the polygon, which creates 2 fewer interior triangles than the number of the polygon’s sides, so the following octagon has --- diagonals from vertex A and forms --- triangles.
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The number of diagonals from one vertex in any polygon is 3 less than the number of sides of the polygon.
If this is true and you know how many sides an octagon has, could you not just subtract 3 from the number of sides of the octagon.
And, then subtract 2 from the number of sides of the octagon to get the interior triangles.