anonymous
  • anonymous
Help Please :) http://prntscr.com/92ni5u
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
lochana
  • lochana
actually you don't need to draw graphs. you can substitute given x value in 2 equation and select the system gives same value for both y.
anonymous
  • anonymous
? Im confused
lochana
  • lochana
well, take first system y = x^2 y = 4x + 2 and we are given x = -0.4 now put that value in those two equations y = (-0.4)^2 = 0.16 y = 4(-0.4) + 2 = 0.4

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More answers

lochana
  • lochana
see, y values are not same. that means x = -0.4 is not a solution for 2 equations.
lochana
  • lochana
so first one is not an answer
lochana
  • lochana
so first one is not an answer
lochana
  • lochana
get it?
anonymous
  • anonymous
So would it be C?
lochana
  • lochana
yes. you are correct:)
anonymous
  • anonymous
Thank you,Do uu think you coul help me with two more diffucult problems please?
lochana
  • lochana
sure
anonymous
  • anonymous
Thank youu !:D Okaii Before we start are these two correct? http://prntscr.com/92notk
lochana
  • lochana
first one is not right.
lochana
  • lochana
you want to put x value of pairs in equations and see y comes up
lochana
  • lochana
same thing like before
anonymous
  • anonymous
So the first is A?
lochana
  • lochana
take (-1,2) y = x^2 + 1 y = 3x -1 now take x value of (-1,2). that is x = -1. now put in equations y = (-1)^2 + 1 = 2 y = 3(-1) -1 = -4 (-1,2) is not an answer because y is not 2 for both equations
lochana
  • lochana
try others like that. there is one solution. I can see it:)
anonymous
  • anonymous
Wait would it be B? Since Y isnt 2 for both sides
lochana
  • lochana
not B. (-1,2) doesn't work here. you don't get y = 2 from second equation:(
anonymous
  • anonymous
Okaiii Sorry I was inserting it wrong,Its c..Okaii heres the last one http://prntscr.com/92ntm7
lochana
  • lochana
yes c is the answer. well, you know already the highest point of B. right?
anonymous
  • anonymous
Yes :D
lochana
  • lochana
you say it from the graph
anonymous
  • anonymous
@lochana is correct c is the right answer
lochana
  • lochana
yeah. now we have A(t) = -(t-10)^2 + 455 (A rocket) here (t - 10)^2 is always positive right ?
lochana
  • lochana
it is a square of a number
anonymous
  • anonymous
Is the answer A? :D
lochana
  • lochana
no:)
anonymous
  • anonymous
Oh :( Sorry
lochana
  • lochana
yeah. what i wanted to say the fact that A(t) = -(t-10)^2 + 455 is takes highest value of A(t) when t = 10
anonymous
  • anonymous
So its C?
lochana
  • lochana
noo:(. not A.:(
lochana
  • lochana
not A rocket
anonymous
  • anonymous
Im so confused
lochana
  • lochana
yes. that's because you don't get the highest value of A(t) = -(t-10)^2 + 455
lochana
  • lochana
tell me what must happen to (t-10)^2 to make A(t) highest?
anonymous
  • anonymous
it has to be solved
lochana
  • lochana
no. there is a tricky part.
lochana
  • lochana
can you understand that -(t-10)^2 is always negative??
lochana
  • lochana
because (t- 10)^2 is always positive. it is a square of a number. squares are never become negative:)
lochana
  • lochana
so is (t-10)^2 is postive, then -(t-10)^2 is always negative
lochana
  • lochana
if you understand that. this question is solved
anonymous
  • anonymous
I dont understand
lochana
  • lochana
5^2 is positive. right?
lochana
  • lochana
\(5^2 = +25\)
lochana
  • lochana
right?
anonymous
  • anonymous
Yes
lochana
  • lochana
so \((-5)^2 = +25\) \((t-10)^2 = positive\)
lochana
  • lochana
the key point is that whatever the number be, when you square it, it become positive value
lochana
  • lochana
t -10 is also a number. just like +5, -5
lochana
  • lochana
don't think about the actual value of (t-10)^2. think about sign of it. it is always positive.there is no way ,you get negative values from squaring.
lochana
  • lochana
are you still lost:'(
anonymous
  • anonymous
So the answers B?,Im still kind of lost
lochana
  • lochana
|dw:1447513937603:dw|
lochana
  • lochana
I was trying to explain how you can get the curve for A:(
lochana
  • lochana
A(t) becomes highest at t =10. and A(10) = 455
lochana
  • lochana
now can you tell the answer?
lochana
  • lochana
|dw:1447514420505:dw|
lochana
  • lochana
answer is last one.
anonymous
  • anonymous
Thank youuu So Much for all ur help:D
lochana
  • lochana
what happen? where were you stuck?
lochana
  • lochana
anyways. try similar questions. you will get better:)
lochana
  • lochana
bye
anonymous
  • anonymous
Yes i was stuck..i had to use all the techniques to understand
lochana
  • lochana
now okay? :)

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