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actually you don't need to draw graphs. you can substitute given x value in 2 equation and select the system gives same value for both y.
? Im confused
well, take first system y = x^2 y = 4x + 2 and we are given x = -0.4 now put that value in those two equations y = (-0.4)^2 = 0.16 y = 4(-0.4) + 2 = 0.4
see, y values are not same. that means x = -0.4 is not a solution for 2 equations.
so first one is not an answer
so first one is not an answer
So would it be C?
yes. you are correct:)
Thank you,Do uu think you coul help me with two more diffucult problems please?
Thank youu !:D Okaii Before we start are these two correct? http://prntscr.com/92notk
first one is not right.
you want to put x value of pairs in equations and see y comes up
same thing like before
So the first is A?
take (-1,2) y = x^2 + 1 y = 3x -1 now take x value of (-1,2). that is x = -1. now put in equations y = (-1)^2 + 1 = 2 y = 3(-1) -1 = -4 (-1,2) is not an answer because y is not 2 for both equations
try others like that. there is one solution. I can see it:)
Wait would it be B? Since Y isnt 2 for both sides
not B. (-1,2) doesn't work here. you don't get y = 2 from second equation:(
Okaiii Sorry I was inserting it wrong,Its c..Okaii heres the last one http://prntscr.com/92ntm7
yes c is the answer. well, you know already the highest point of B. right?
you say it from the graph
@lochana is correct c is the right answer
yeah. now we have A(t) = -(t-10)^2 + 455 (A rocket) here (t - 10)^2 is always positive right ?
it is a square of a number
Is the answer A? :D
Oh :( Sorry
yeah. what i wanted to say the fact that A(t) = -(t-10)^2 + 455 is takes highest value of A(t) when t = 10
So its C?
noo:(. not A.:(
not A rocket
Im so confused
yes. that's because you don't get the highest value of A(t) = -(t-10)^2 + 455
tell me what must happen to (t-10)^2 to make A(t) highest?
it has to be solved
no. there is a tricky part.
can you understand that -(t-10)^2 is always negative??
because (t- 10)^2 is always positive. it is a square of a number. squares are never become negative:)
so is (t-10)^2 is postive, then -(t-10)^2 is always negative
if you understand that. this question is solved
I dont understand
5^2 is positive. right?
\(5^2 = +25\)
so \((-5)^2 = +25\) \((t-10)^2 = positive\)
the key point is that whatever the number be, when you square it, it become positive value
t -10 is also a number. just like +5, -5
don't think about the actual value of (t-10)^2. think about sign of it. it is always positive.there is no way ,you get negative values from squaring.
are you still lost:'(
So the answers B?,Im still kind of lost
I was trying to explain how you can get the curve for A:(
A(t) becomes highest at t =10. and A(10) = 455
now can you tell the answer?
answer is last one.
Thank youuu So Much for all ur help:D
what happen? where were you stuck?
anyways. try similar questions. you will get better:)
Yes i was stuck..i had to use all the techniques to understand
now okay? :)