Help Please :)
http://prntscr.com/92ni5u

- anonymous

Help Please :)
http://prntscr.com/92ni5u

- Stacey Warren - Expert brainly.com

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- chestercat

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- lochana

actually you don't need to draw graphs. you can substitute given x value in 2 equation and select the system gives same value for both y.

- anonymous

? Im confused

- lochana

well, take first system
y = x^2
y = 4x + 2
and we are given x = -0.4
now put that value in those two equations
y = (-0.4)^2 = 0.16
y = 4(-0.4) + 2 = 0.4

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## More answers

- lochana

see, y values are not same. that means x = -0.4 is not a solution for 2 equations.

- lochana

so first one is not an answer

- lochana

so first one is not an answer

- lochana

get it?

- anonymous

So would it be C?

- lochana

yes. you are correct:)

- anonymous

Thank you,Do uu think you coul help me with two more diffucult problems please?

- lochana

sure

- anonymous

Thank youu !:D Okaii Before we start are these two correct?
http://prntscr.com/92notk

- lochana

first one is not right.

- lochana

you want to put x value of pairs in equations and see y comes up

- lochana

same thing like before

- anonymous

So the first is A?

- lochana

take (-1,2)
y = x^2 + 1
y = 3x -1
now take x value of (-1,2). that is x = -1. now put in equations
y = (-1)^2 + 1 = 2
y = 3(-1) -1 = -4
(-1,2) is not an answer because y is not 2 for both equations

- lochana

try others like that. there is one solution. I can see it:)

- anonymous

Wait would it be B? Since Y isnt 2 for both sides

- lochana

not B. (-1,2) doesn't work here. you don't get y = 2 from second equation:(

- anonymous

Okaiii Sorry I was inserting it wrong,Its c..Okaii heres the last one
http://prntscr.com/92ntm7

- lochana

yes c is the answer.
well, you know already the highest point of B. right?

- anonymous

Yes :D

- lochana

you say it from the graph

- anonymous

@lochana is correct c is the right answer

- lochana

yeah. now we have A(t) = -(t-10)^2 + 455 (A rocket)
here (t - 10)^2 is always positive right ?

- lochana

it is a square of a number

- anonymous

Is the answer A? :D

- lochana

no:)

- anonymous

Oh :( Sorry

- lochana

yeah. what i wanted to say the fact that
A(t) = -(t-10)^2 + 455 is takes highest value of A(t) when t = 10

- anonymous

So its C?

- lochana

noo:(. not A.:(

- lochana

not A rocket

- anonymous

Im so confused

- lochana

yes. that's because you don't get the highest value of A(t) = -(t-10)^2 + 455

- lochana

tell me what must happen to (t-10)^2 to make A(t) highest?

- anonymous

it has to be solved

- lochana

no. there is a tricky part.

- lochana

can you understand that -(t-10)^2 is always negative??

- lochana

because (t- 10)^2 is always positive. it is a square of a number. squares are never become negative:)

- lochana

so is (t-10)^2 is postive, then -(t-10)^2 is always negative

- lochana

if you understand that. this question is solved

- anonymous

I dont understand

- lochana

5^2 is positive. right?

- lochana

\(5^2 = +25\)

- lochana

right?

- anonymous

Yes

- lochana

so
\((-5)^2 = +25\)
\((t-10)^2 = positive\)

- lochana

the key point is that whatever the number be, when you square it, it become positive value

- lochana

t -10 is also a number. just like +5, -5

- lochana

don't think about the actual value of (t-10)^2. think about sign of it. it is always positive.there is no way ,you get negative values from squaring.

- lochana

are you still lost:'(

- anonymous

So the answers B?,Im still kind of lost

- lochana

|dw:1447513937603:dw|

- lochana

I was trying to explain how you can get the curve for A:(

- lochana

A(t) becomes highest at t =10. and A(10) = 455

- lochana

now can you tell the answer?

- lochana

|dw:1447514420505:dw|

- lochana

answer is last one.

- anonymous

Thank youuu So Much for all ur help:D

- lochana

what happen? where were you stuck?

- lochana

anyways. try similar questions. you will get better:)

- lochana

bye

- anonymous

Yes i was stuck..i had to use all the techniques to understand

- lochana

now okay? :)

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