A man plays a game in the following manner: he pays $20 to throw a die and he will be paid $(n^2+5) if the number n turns up. What is his expected gain in each trial and what is his expected gain in 30 trials?
Is it correct to calculate the expected gain in each trial by:
(1/6)*(5*6+1^2+2^2+3^2+4^2+5^2+6^2)
=121/6 ?
And what is the difference between one trial and 30 trials?

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if i recall correctly ... expected value is:
$won * P(win) + $lost * P(lose)

30 trials might indicate a discrete probability function as opposed to a normal distribution

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