anonymous
  • anonymous
Need some correction about this Probability problem: The number of defective products produced by a factory in one day is modeled by a random variable with density Poisson(k;14.3). What is the probability that at least 14 defective products are produced in a single day?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
the answer support to be 0.42202 or 0.5670
anonymous
  • anonymous
which formula should I use \[1-\sum_{0}^{13} e^{-\lambda} \frac{ \lambda^n }{ n! }\] or \[\sum_{0}^{13} e^{-\lambda} \frac{ \lambda^n }{ n! }\] for this problem
amistre64
  • amistre64
what does "at least" mean?

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anonymous
  • anonymous
i guess is mean aprox less than and equal to 14 ?
amistre64
  • amistre64
at least14 ... the least is 14 you must be at least this tall, to ride this ride ... anyone shorter cannot get in you must be at least this age to see this movie ... anyone younger cannot get in you have to go at least this speed to qualify for the race ... any slower does not get in. at least 14, includes: 14,15,16,17,18,...
anonymous
  • anonymous
i see
anonymous
  • anonymous
that going to be infinity with 14
amistre64
  • amistre64
P(0)+P(1)+...+P(13)+P(14)+P(15)+... = 1 P(14)+P(15)+... = 1 - [P(0)+P(1)+...+P(13)]
anonymous
  • anonymous
1-P(X<= 13) = 1-[ P(X=0) + P(X=1) + ... + P(X=13)]
anonymous
  • anonymous
do that mean both are the same, must be equal to 1
anonymous
  • anonymous
P(X=0) + P(X=1) + P(X=2) + ... = 1 P(X<=13) + P(X>=14) = 1 you want P(X>=14) = 1- P(X<=13)
amistre64
  • amistre64
|dw:1447608766607:dw|
anonymous
  • anonymous
remember, poisson is a discrete distibution so x cannot take on values inbetweeen 13 and 14.
anonymous
  • anonymous
that mean i need to use first formula for this problem ?
amistre64
  • amistre64
yes

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