anonymous
  • anonymous
Write the sum using summation notation, assuming the suggested pattern continues. -4 + 5 + 14 + 23 + ... + 131 Please explain how you got your answer.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
what are you adding each time?
anonymous
  • anonymous
9
anonymous
  • anonymous
right so maybe you can use something like \[\sum_{k=0}^n -4+9k\]

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More answers

anonymous
  • anonymous
course you still got to figure out what \(n\) is
anonymous
  • anonymous
Im assuming it's infinity considering the other choice I have is 15 and the 15th term would not be 131
anonymous
  • anonymous
\[-4+9n=131\] what is \(n\)?
anonymous
  • anonymous
oh... 15....
anonymous
  • anonymous
ahah. Thanks!
anonymous
  • anonymous
ok so if \[\sum_{k=0}^{15} -4+9k\] is a choice, pick that one
anonymous
  • anonymous
yw
anonymous
  • anonymous
It is. Mind helping me with another?
anonymous
  • anonymous
go ahead and ask, maybe i can helpl
anonymous
  • anonymous
Write the sum using summation notation, assuming the suggested pattern continues. 16 + 25 + 36 + 49 + ... + n^2 + ...
anonymous
  • anonymous
does it really have \(...\)?
anonymous
  • anonymous
yes
anonymous
  • anonymous
then just go with \[\sum_{n=4}^{\infty}n^2\]
anonymous
  • anonymous
silly because you cannot add all this stuff up but whatever
anonymous
  • anonymous
Why n=4 at the bottom?
anonymous
  • anonymous
what number starts the summation ?
anonymous
  • anonymous
Don't know. Would've said 16.
anonymous
  • anonymous
yes it is
anonymous
  • anonymous
and what number squared gives 16?
anonymous
  • anonymous
4. So It's the square root of the first term that goes on the bottom???
anonymous
  • anonymous
\[\sum_{n=4}^{\infty}n^2=4^2+5^2+6^2+...\]
anonymous
  • anonymous
each term is the square of some number
anonymous
  • anonymous
oh I see
anonymous
  • anonymous
starting with 16, that is the square of 4
anonymous
  • anonymous
Thanks again!
anonymous
  • anonymous
yw again

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