beautifulpansophy
  • beautifulpansophy
A positive point charge q = +2.50 nC is located at x = 1.20 m and a negative charge of -2q = -5.00 nC is located at the origin. (a) Find a symbolic expression for the potential on the x – axis at an arbitrary point P between the two charges. (b) Find the electric potential at x = 0.600 m. (c) Find the point along the x –axis between the two charges where the electric potential is zero.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Michele_Laino
  • Michele_Laino
here we have to apply the superposition principle, namely the requested potential, is given by the algebraic sum of the single potentials: |dw:1449169405601:dw| \[\huge V\left( P \right) = K\frac{{ - 2q}}{x} + K\frac{q}{{d - x}}\] where, as usual, \(K=9 \cdot 10^9\)
beautifulpansophy
  • beautifulpansophy
Thank you! Physics is not my strong point. For part b) would i just use the same equation and substitute 0.600 m in for x?
anonymous
  • anonymous
Yes. Plug in x = 0.600m and d = 1.20m

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anonymous
  • anonymous
Then for c). Plug in 0 for V(P) and solve for x, which is with respect to the origin.

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