anonymous
  • anonymous
cotx = -2 and secx < 0 How do I find sinx, cosx, and tanx?
Trigonometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
r u given any more info?
jhonyy9
  • jhonyy9
so you know that cot x = cos x / sin x and tan x = 1/cot x yes ? hope this will help you
guptalakshay558
  • guptalakshay558
Given :- Cotx = -2 secx<0 Approach:- We know cotx and secx are both together negative in only 2nd quadrant Solution :- cotx =-2 so, tanx = -1/2 (cotx = 1/tanx) sinx = \[1/\sqrt{5}\]( sinx is positive in second quadrant) cos= \[-2/\sqrt{5}\] (cos x is negative in seond quadrent )

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