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Find the vertical asymptotes, if any, of the graph of the rational function. g(x)= x over x^2 -1
answer x= 1, x=-1
can u draw out the eqn plz @Destinyyyy ?
ever use wolfram site 4 math help?
Nope.. I use mathway sometimes
they are similar...check it out: http://www.wolframalpha.com/input/?i=f%28x%29%3Dx%2F%28x%5E2-1%29&lk=4&num=1
But its doesnt say vertical asymptotes anywhere
true but u can kinda "eye-ball" them right? ;)
hint: those are the lines where the denominator becomes zero...
Mathway says my answer is right so Ill just stick with it..
hahahaa may i know wat they are plz?
I said it above.. answer x= 1, x=-1
ooops sorry - right u are again :)
Okay.. I thought you were saying I was wrong.
no, i didnt read thro ur posts...sorry! but hey now u know wolframalpha - its a pretty cool site! :)
Next question.. Graph the rational function. f(x)= 4x^2 over x^2 -36
wanna try it out on wolfram? ;)
I just tried and it did 4 * x^2 over x^2 -36 :(
yes u need to be careful about the sequence; dats why i asked u to write it out a few times. here is how it should look like; note the brackets: http://www.wolframalpha.com/input/?i=f%28x%29%3D4x%5E2%2F%28x%5E2-36%29
Its exactly the same as mine
alright then what IS ur eqn?
But I need to remember how to solve it. I cant use a website when I take my final on Saturday
well graphing an eqn is different from solving it....ur Q asks u to graph it right?
Yes. I need to know how to graph it my self. Not with a website.
OK so the plot is how the eqn will look like...
Yeah.. I already figured that out.
if u need to graph an eqn in an exam, u either recognize it is a standard form like a circle, parabola or so; or like in this case, u pretty much have to put in x=-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 n calculate the y values.
can u use a graphing calculator like one of those made by Ti?
Yeah I have one. But I have no clue how to graph on it. Im absolutely sure im suppose to solve it out on paper to be able to graph it.
I guess we can skip it and come back to it
yep...wuld require sum1 better in explanation than me to show u how! lol
Solve the polynomial inequality and graph the solution set on a number number line. Express the solution set in interval notation. x^2 -2x-8<0
I got 1+- 1i square root 7 ... I know I messed up some where
solving inequality means solving the eqn 1st...
unlikely dats the ans as it involves i which cannot be shown on a real number line....
x^2 -2x-8=0 u can solve by grouping or just the quadratic eqn...either way will work :)
I see where I messed up
correct now just plot the inequality on the number line n u are done!
careful about which part(s) of the number line where f(x) < 0