anonymous
  • anonymous
2x^2 -3x=x^2+10 solve by factoring
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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skullpatrol
  • skullpatrol
Any ideas? :-)
anonymous
  • anonymous
2x^2-3x=x^2+10 2x^-x^2=10+3x x^2=10+3x x=5
anonymous
  • anonymous
i am right?

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anonymous
  • anonymous
i think there should be two answers for x..
DanJS
  • DanJS
i think they want you to move it into standard form first y = ax^2 + bx + c = 0
DanJS
  • DanJS
x^2 - 3x - 10 = 0 (x )*(x ) = 0
anonymous
  • anonymous
ok guys) i will try to do for this formula)
anonymous
  • anonymous
(x-5)(x+2)
DanJS
  • DanJS
use factors of 10 to try and create a -3 in the middle
DanJS
  • DanJS
+2 and -3
DanJS
  • DanJS
put those in and expand to see if it worked.. (x + 2)*(x - 3) = 0
anonymous
  • anonymous
oh okay thanks guys!!! :)
DanJS
  • DanJS
welcome, so either of those ( ) can be zero to make it true, x=-2 or x = 3
DanJS
  • DanJS
or you can always apply the quadratic formula and see what th evalues are to give a hint as to the factors
anonymous
  • anonymous
thank you very much

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