Saylilbaby
  • Saylilbaby
what is a simplified trigonometric expression for csc 0 sin 0-sin^2 0? A.sec^20 B.cos^2 0 C.1-tan^2 0 D.tan0-sin^2 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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DanJS
  • DanJS
write everything in terms of sin and cos first
DanJS
  • DanJS
csc(a) = 1/sin(a)
Saylilbaby
  • Saylilbaby
For the function y=tan 0, which angle measure has the same value as 2pie/3? A.5pie/3 B.7pie/6 C.4pie/3 D.pie/6

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DanJS
  • DanJS
so you get 1 - sin^2(a)
DanJS
  • DanJS
and recall sin^2 + cos^2 = 1 ,
DanJS
  • DanJS
so, it is the same as cos^2(a)
DanJS
  • DanJS
remember the tangent has a period of pi
Saylilbaby
  • Saylilbaby
what are the period and amplitude of the function y=2sin4 0? A.pie/2 and 2 B.pie and 4 C.pie /2 and 4 D.pie/2 and 1
DanJS
  • DanJS
add or subtract any multiple of pi
Saylilbaby
  • Saylilbaby
so 1 is B @DanJS
DanJS
  • DanJS
yeah, just have to rewrite csc as 1/sin instead, then you get 1 - sin^2
DanJS
  • DanJS
which is an identity, sin^2 + cos^2 = 1
Saylilbaby
  • Saylilbaby
is 2 B? @DanJS
DanJS
  • DanJS
tangent has a period of pi, rotation by pi will produce the same value
Saylilbaby
  • Saylilbaby
so A @DanJS
DanJS
  • DanJS
2/3 pi + pi 2/3 pi + 2pi . . .
Saylilbaby
  • Saylilbaby
c @DanJS
DanJS
  • DanJS
yeah A works there, 2/3 pi + pi = 5/3 pi
DanJS
  • DanJS
tangent of 2/3 pi = tangent of 5/3 pi try it
Saylilbaby
  • Saylilbaby
i though c cause 2*2 is 4 and the denominator stays the same @DanJS
DanJS
  • DanJS
not doubling the angle, adding pi to it. 3/3 pi
DanJS
  • DanJS
2/3 pi + 3/3 pi = 5/3 pi
DanJS
  • DanJS
none of the others work, keep adding pi 8/3 pi 11/3 pi
Saylilbaby
  • Saylilbaby
i see now okay next is 3 B @DanJS
DanJS
  • DanJS
y = 2*sin^4(a)
DanJS
  • DanJS
the amplitude is usually that number out front, A*sin(x), but here there is one difference
Saylilbaby
  • Saylilbaby
by how much does the mean of the data set below change if the outlier is removed? round your answer to the nearest tenth, if necessary. 8,6,9,12,19,7,10,8 A.0.5 B.0.6 C.1.3 D.2.4
DanJS
  • DanJS
sin(x) is always between -1 and 1 (sin(x))^4 is always possitive because of the even power, so sin^4(x) is between 0 and 1
Saylilbaby
  • Saylilbaby
so is it B. pie and 4 @DanJS
DanJS
  • DanJS
which one is the function \[y = \sin^4(x)\] or \[y = \sin(4x)\]
DanJS
  • DanJS
what are the period and amplitude of the function y=2sin4 0? A.pie/2 and 2 B.pie and 4 C.pie /2 and 4 D.pie/2 and 1
Saylilbaby
  • Saylilbaby
a @DanJS
DanJS
  • DanJS
is the 4 a power or part of the angle
DanJS
  • DanJS
the first power one, amplitude is 1 period is pi second one is amplitude 2, period T=2pi/4 = pi/2
DanJS
  • DanJS
here is a little thing on the general form for trig function http://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.754992.html
Saylilbaby
  • Saylilbaby
so its A @DanJS
DanJS
  • DanJS
but the 4 power keeps the sin function positive, so th eamplitude is not 2, it would be half of it, only positive values
DanJS
  • DanJS
if the function is y = 2*sin(4x) , not sin to the 4th power, then the answer is A yeah
Saylilbaby
  • Saylilbaby
c.pie/2 and4 @DanJS
DanJS
  • DanJS
if you have y = A*sin(Bx) the amplitude is A the period is (2pi)/B
DanJS
  • DanJS
for y = 2*sin(4x) period is (2pi)/4 or pi/2 amplitude is 2
Saylilbaby
  • Saylilbaby
a,b,c or d @DanJS

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