anonymous
  • anonymous
(x-2)^2=100 Solve the quadratic function with square roots
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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tkhunny
  • tkhunny
It's already nicely set up for you. Find the two square roots and you're gold.
anonymous
  • anonymous
would the answer be 12?
tkhunny
  • tkhunny
That's one. Where did the other one go? It helps to write out your process, not just your answer.

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More answers

anonymous
  • anonymous
theres another one?
tkhunny
  • tkhunny
Two. Hint: (2)^2 = 4 (-2)^2 = 4
xapproachesinfinity
  • xapproachesinfinity
if \[x^2=a \Longrightarrow |x|=\sqrt{a}\]
DanJS
  • DanJS
\[\large \sqrt{u^2}=\left| u \right|\]
DanJS
  • DanJS
even power
xapproachesinfinity
  • xapproachesinfinity
the reasoning is given by @tkhunny when you square positive and number like (-2)^2 (2)^2 the result is the same 4
xapproachesinfinity
  • xapproachesinfinity
that is why we are using absolute value
anonymous
  • anonymous
If I squared (x-2) all together and 100, I would get x-2=10 correct?
tkhunny
  • tkhunny
Well, after all that, did you find the second one? Here's how you find the first one: (x-2)^2 = 100 Square Root x-2 = 10 ==> x = 12 What you did not do was this: Square Root x-2 = -10 ==> What?
DanJS
  • DanJS
yes, if you square root something that is squared like root of (x-2)^2, that something can be positive or negative, \[\sqrt{(x-2)^2} = \left| x-2 \right| = 10\]
DanJS
  • DanJS
solving absolute value probs, that x-2 can be +10 or -10 2 values for x as @tkhunny showed above

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