calculusxy
  • calculusxy
How to find the quadratic equation from a data table?
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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calculusxy
  • calculusxy
Input = 8, 1, -7, -17 Output = -4, -3, 1, 5
calculusxy
  • calculusxy
@Nnesha
calculusxy
  • calculusxy
please help me quickly!

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calculusxy
  • calculusxy
@mathmale
anonymous
  • anonymous
1 Attachment
Nnesha
  • Nnesha
the standard form equation is y=ax^2+bx+C first look at the table and see how the output values are changing ?|dw:1449204372348:dw|
calculusxy
  • calculusxy
|dw:1449204681189:dw|
mathmale
  • mathmale
Hello! If you're to find a quadratic equation (formula), assume that it has the form y=ax^2 + bx + c. Taking data from the first line of your data table: if x is 8, y is -4, we get -4=a(8)^2 + b(8) + c. Do the same thing for the next 2 data points. You will end up with three quadratic equations with a, b and c unknown. Your task is to determine a, b and c. Once you have a, b and c, just write the quadratic: y = ax^2 +bx + c. Substitute the x and y from your fourth data point into this equation to check whether the equation is true or not.
calculusxy
  • calculusxy
Is there is an easier process than that?
xapproachesinfinity
  • xapproachesinfinity
there is sequence way
calculusxy
  • calculusxy
is it easier?
xapproachesinfinity
  • xapproachesinfinity
I guess it lengthy for this problem you have started already with that when you are trying the patterns
xapproachesinfinity
  • xapproachesinfinity
taking the differences of the outputs
xapproachesinfinity
  • xapproachesinfinity
http://mathematicsi.com/quadratic-sequences/
Nnesha
  • Nnesha
the way i was doing u have to find the difference again between 1,4,4 how the values are changing ?
calculusxy
  • calculusxy
1 to 4 = 3 4 to 4 = 0
xapproachesinfinity
  • xapproachesinfinity
@Nnesha is referring to the same thing lol second difference must be constant ( not changing to other values)
calculusxy
  • calculusxy
so this is not a quadratic?
xapproachesinfinity
  • xapproachesinfinity
try the usual way and see if that true sequence way is dealing with discrete values not continuous values
calculusxy
  • calculusxy
i don't know what to do!
Nnesha
  • Nnesha
find the 3rd difference and see if u get constant bec if it's quadratic then the 2nd difference suppose to be constant
Nnesha
  • Nnesha
supposed*
xapproachesinfinity
  • xapproachesinfinity
mathmale has explained it you take 3 set of values x and y plug them into y=ax^2+bx+c you will get three simultaneous equations to solve for a,b, and c
Nnesha
  • Nnesha
Plus x values should be constant. for quadratic 2nd difference must be constant and for cubic function 3rd difference should be constant

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