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Input = 8, 1, -7, -17 Output = -4, -3, 1, 5
please help me quickly!
the standard form equation is y=ax^2+bx+C first look at the table and see how the output values are changing ?|dw:1449204372348:dw|
Hello! If you're to find a quadratic equation (formula), assume that it has the form y=ax^2 + bx + c. Taking data from the first line of your data table: if x is 8, y is -4, we get -4=a(8)^2 + b(8) + c. Do the same thing for the next 2 data points. You will end up with three quadratic equations with a, b and c unknown. Your task is to determine a, b and c. Once you have a, b and c, just write the quadratic: y = ax^2 +bx + c. Substitute the x and y from your fourth data point into this equation to check whether the equation is true or not.
Is there is an easier process than that?
there is sequence way
is it easier?
I guess it lengthy for this problem you have started already with that when you are trying the patterns
taking the differences of the outputs
the way i was doing u have to find the difference again between 1,4,4 how the values are changing ?
1 to 4 = 3 4 to 4 = 0
@Nnesha is referring to the same thing lol second difference must be constant ( not changing to other values)
so this is not a quadratic?
try the usual way and see if that true sequence way is dealing with discrete values not continuous values
i don't know what to do!
find the 3rd difference and see if u get constant bec if it's quadratic then the 2nd difference suppose to be constant
mathmale has explained it you take 3 set of values x and y plug them into y=ax^2+bx+c you will get three simultaneous equations to solve for a,b, and c
Plus x values should be constant. for quadratic 2nd difference must be constant and for cubic function 3rd difference should be constant