anonymous
  • anonymous
Plz help fast Simplify √8•6√5=
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
use a calculator
anonymous
  • anonymous
no find the square root of 8 then multiply by 6 then multiply by the square root of 5
whpalmer4
  • whpalmer4
\[\sqrt{8}*6*\sqrt{5} = 6*\sqrt{8}*\sqrt{5} = 6*\sqrt{8*5} = 6*\sqrt{40}\]\[ = 6*\sqrt{4*10} = 6*\sqrt{4}*\sqrt{10} = 6*2*\sqrt{10} = \]

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anonymous
  • anonymous
wolframalpha.com agrees with my answer
whpalmer4
  • whpalmer4
The problem asks to simplify, not find the decimal...
anonymous
  • anonymous
oh very true
whpalmer4
  • whpalmer4
as both \(\sqrt{8}\) and \(\sqrt{5}\) are irrational, it is not possible to multiply them accurately except by doing so symbolically, which is what we did.
whpalmer4
  • whpalmer4
I should say exactly, not accurately...
anonymous
  • anonymous
So what's my answer going to be please
whpalmer4
  • whpalmer4
\(6*2*\sqrt{10} = \) ? what is \(6*2=\) what do you get if you multiply that by \(\sqrt{10}\) hint: \(a * \sqrt{b} = a\sqrt{b}\)
anonymous
  • anonymous
2^2=2
anonymous
  • anonymous
I really don't know
whpalmer4
  • whpalmer4
You don't know what \(6*2=\) seriously?
anonymous
  • anonymous
12
whpalmer4
  • whpalmer4
okay, and a number times a square root of a number is written number square root other number. \[2*\sqrt{3} = 2\sqrt{3}\] \[12 * \sqrt{10} = \]
anonymous
  • anonymous
I Don't know
anonymous
  • anonymous
Is it the finale answer √120
whpalmer4
  • whpalmer4
I can't make it any plainer than I just did...if you multiply a number by the square root of another number, you just write down the first number followed by the square root sign and the other number, just like I did for 2 * the square root of 3.
whpalmer4
  • whpalmer4
No, if you move a number from the inside of the square root to the outside, you have to take the square root of the number. \[\sqrt{32} = \sqrt{16*2} = \sqrt{16}*\sqrt{2} = 4*\sqrt{2} = 4\sqrt{2}\] Going the other way, if you move a number inside the square root sign, you have to square it: \[10\sqrt{2} = \sqrt{10*10}*\sqrt{2} = \sqrt{10*10*2} = \sqrt{200}\] So, if you wanted to move that \(12\) inside the square root sign, it would be: \[12\sqrt{10} = \sqrt{12*12}*\sqrt{10}=\sqrt{12*12*10}= \sqrt{1440}\]
whpalmer4
  • whpalmer4
Your answer is simply \(12\sqrt{10}\) — that is the simplified form of \(\sqrt{8}*6*\sqrt{5}\)
anonymous
  • anonymous
Ohh ok thank you
whpalmer4
  • whpalmer4
I suggest you ask your teacher to go over this with you again, as it is very important, and you'll have no end of trouble if you make mistakes...
anonymous
  • anonymous
Ok thanks I am homeschool
whpalmer4
  • whpalmer4
Hmm. Have you tried watching the Khan Academy (http://khanacademy.org) videos? They are generally very good, I find. Here's the section on square roots: https://www.khanacademy.org/math/pre-algebra/exponents-radicals/radical-radicals/v/understanding-square-roots I think you would probably be well-served to go through the whole pre-algebra lecture series. Not all in one afternoon, of course! :-)
anonymous
  • anonymous
Thanks

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