2nd|http://prntscr.com/9a9ene

- Lemanual

2nd|http://prntscr.com/9a9ene

- Stacey Warren - Expert brainly.com

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- katieb

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- Lemanual

@iGreen

- iGreen

Find the inverse first

- iGreen

\(\sf y = \dfrac{x - 7}{3}\)
Switch 'x' and 'y'
\(\sf x = \dfrac{y - 7}{3}\)
Now solve for 'y'

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## More answers

- iGreen

Can you do that?

- Lemanual

Not really sure but is this the inverse? 3y = (x-7)?

- iGreen

We divide 3 to both sides, not multiply, it would actually give us:
\(\sf \dfrac{1}{3}x = x - 7\)

- iGreen

Now add 7 to both sides to complete the inverse

- iGreen

Sorry that's \(\sf \dfrac{1}{3}x = y - 7\)

- Lemanual

10y =x?

- iGreen

No, just add 7 to both sides, you can't combine anything.

- Lemanual

So 7 + 3y = x?

- iGreen

1/3x*

- iGreen

\(\sf 7 + \dfrac{1}{3}x = y\)

- iGreen

Now plug in 4 for 'x' and solve

- Lemanual

So the correct answer would be 19?

- iGreen

No..how did you get that?

- Lemanual

Idk I got confused when you said plug in 4 for x and solve I was debating on 19 or 33 but Idk I''m not that good in math : /

- Lemanual

I'm

- iGreen

19 is correct

- iGreen

I made a misstake lol

- iGreen

mistake*

- Lemanual

Oh yay I was right :D what mistake did you make?

- iGreen

We multiply 3 to both sides, not divide..so it should've been \(\sf y = 3x + 7\), and plugging 4 in gives us 19.

- iGreen

I divided 3 to both sides instead of multiplied, my bad.

- Lemanual

Ohhh It's ok But can you check this last question to see if I got it right it's with x and y chart

- Lemanual

http://prntscr.com/9a9m3r

- Lemanual

@iGreen

- anonymous

@jigglypuff314

- Lemanual

:O I jigglypuff fan I love her in super smash :OOO

- anonymous

lol

- Lemanual

:P Do you know if I'm right on this? http://prntscr.com/9a9m3r

- anonymous

@brooke2353

- anonymous

I don't but this person said she would help

- Lemanual

Ok, Thanks

- anonymous

no plroblem

- anonymous

*problem

- Lemanual

I had to turn it in I got it wrong but I know what answer it was ty tho for trying to help again bye I'm going to fan you.

- anonymous

Oh ok thanks, sorry I couldn't help

- Lemanual

It's cool bro I'm taking another quiz rn do you like math or you're not a big fan of it.

- anonymous

I'm better at English than math but I could try to find people who can help

- Lemanual

It's coolio I can do this one but I might take a English test you never know :O :P You're cool, How old are you?

- jigglypuff314

am I too late?

- anonymous

I'm in 8th grade

- iGreen

Lol

- Lemanual

I'm in the 9th :D

- Lemanual

O_O what

- Lemanual

JIGGLYPUFF :D

- anonymous

Ya I think he got his question answered but he might need help later @jigglypuff314

- Lemanual

Jiggly goner V_V

- anonymous

V_V R.I.P

- Lemanual

@iGreen @brooke2353 Do you guys know the answer to this one?|http://prntscr.com/9a9w9q

- Lemanual

@twister02 lol!

- jigglypuff314

try multiplying top and bottom by xy

- Lemanual

Hmmm hold on

- jigglypuff314

for the numerator you would get
(xy)((1/x) + (1/y)) = (xy)(1/x) + (xy)(1/y) = y + x
and same idea for the denominator (except with a negative in the middle)

- Lemanual

:O Interesting I think I know the answer :O

- brooke2353

idk

- Lemanual

Is it D :O x+y/x-y?

- jigglypuff314

look at the order in the numerator that I got
try again

- Lemanual

Awww V_V

- Lemanual

I keep getting x+y/x-y : /

- jigglypuff314

\[(\frac{ 1 }{ x } - \frac{1}{y})*(\frac{xy}{1})\]

- jigglypuff314

\[\frac{ xy }{ x } - \frac{xy}{y}\]

- Lemanual

Ohhhh

- Lemanual

So C right?

- jigglypuff314

;-;

- Lemanual

D:::

- Lemanual

Meh confused I'm not that good at mathh

- jigglypuff314

reread every one of my previous comments

- Lemanual

Oh.. My.. God.. :O ;-;

- Lemanual

Okay.. V_V

- brooke2353

lmfao

- Lemanual

I THINK I GOT IT I think<< It's A

- jigglypuff314

good

- Lemanual

Yay :D

- Lemanual

Thanks guys again so much I passed my Algebra class now :D I'm all caught up : )

- Lemanual

Thanks tho for your help really ; ) *wink* *wink* :D

- Lemanual

Seeya tomorrow guys I will be on everyday probs not weekends tho bye and thanks for the help : )

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