Lemanual
  • Lemanual
2nd|http://prntscr.com/9a9ene
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Lemanual
  • Lemanual
@iGreen
iGreen
  • iGreen
Find the inverse first
iGreen
  • iGreen
\(\sf y = \dfrac{x - 7}{3}\) Switch 'x' and 'y' \(\sf x = \dfrac{y - 7}{3}\) Now solve for 'y'

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

iGreen
  • iGreen
Can you do that?
Lemanual
  • Lemanual
Not really sure but is this the inverse? 3y = (x-7)?
iGreen
  • iGreen
We divide 3 to both sides, not multiply, it would actually give us: \(\sf \dfrac{1}{3}x = x - 7\)
iGreen
  • iGreen
Now add 7 to both sides to complete the inverse
iGreen
  • iGreen
Sorry that's \(\sf \dfrac{1}{3}x = y - 7\)
Lemanual
  • Lemanual
10y =x?
iGreen
  • iGreen
No, just add 7 to both sides, you can't combine anything.
Lemanual
  • Lemanual
So 7 + 3y = x?
iGreen
  • iGreen
1/3x*
iGreen
  • iGreen
\(\sf 7 + \dfrac{1}{3}x = y\)
iGreen
  • iGreen
Now plug in 4 for 'x' and solve
Lemanual
  • Lemanual
So the correct answer would be 19?
iGreen
  • iGreen
No..how did you get that?
Lemanual
  • Lemanual
Idk I got confused when you said plug in 4 for x and solve I was debating on 19 or 33 but Idk I''m not that good in math : /
Lemanual
  • Lemanual
I'm
iGreen
  • iGreen
19 is correct
iGreen
  • iGreen
I made a misstake lol
iGreen
  • iGreen
mistake*
Lemanual
  • Lemanual
Oh yay I was right :D what mistake did you make?
iGreen
  • iGreen
We multiply 3 to both sides, not divide..so it should've been \(\sf y = 3x + 7\), and plugging 4 in gives us 19.
iGreen
  • iGreen
I divided 3 to both sides instead of multiplied, my bad.
Lemanual
  • Lemanual
Ohhh It's ok But can you check this last question to see if I got it right it's with x and y chart
Lemanual
  • Lemanual
http://prntscr.com/9a9m3r
Lemanual
  • Lemanual
@iGreen
anonymous
  • anonymous
@jigglypuff314
Lemanual
  • Lemanual
:O I jigglypuff fan I love her in super smash :OOO
anonymous
  • anonymous
lol
Lemanual
  • Lemanual
:P Do you know if I'm right on this? http://prntscr.com/9a9m3r
anonymous
  • anonymous
@brooke2353
anonymous
  • anonymous
I don't but this person said she would help
Lemanual
  • Lemanual
Ok, Thanks
anonymous
  • anonymous
no plroblem
anonymous
  • anonymous
*problem
Lemanual
  • Lemanual
I had to turn it in I got it wrong but I know what answer it was ty tho for trying to help again bye I'm going to fan you.
anonymous
  • anonymous
Oh ok thanks, sorry I couldn't help
Lemanual
  • Lemanual
It's cool bro I'm taking another quiz rn do you like math or you're not a big fan of it.
anonymous
  • anonymous
I'm better at English than math but I could try to find people who can help
Lemanual
  • Lemanual
It's coolio I can do this one but I might take a English test you never know :O :P You're cool, How old are you?
jigglypuff314
  • jigglypuff314
am I too late?
anonymous
  • anonymous
I'm in 8th grade
iGreen
  • iGreen
Lol
Lemanual
  • Lemanual
I'm in the 9th :D
Lemanual
  • Lemanual
O_O what
Lemanual
  • Lemanual
JIGGLYPUFF :D
anonymous
  • anonymous
Ya I think he got his question answered but he might need help later @jigglypuff314
Lemanual
  • Lemanual
Jiggly goner V_V
anonymous
  • anonymous
V_V R.I.P
Lemanual
  • Lemanual
@iGreen @brooke2353 Do you guys know the answer to this one?|http://prntscr.com/9a9w9q
Lemanual
  • Lemanual
@twister02 lol!
jigglypuff314
  • jigglypuff314
try multiplying top and bottom by xy
Lemanual
  • Lemanual
Hmmm hold on
jigglypuff314
  • jigglypuff314
for the numerator you would get (xy)((1/x) + (1/y)) = (xy)(1/x) + (xy)(1/y) = y + x and same idea for the denominator (except with a negative in the middle)
Lemanual
  • Lemanual
:O Interesting I think I know the answer :O
brooke2353
  • brooke2353
idk
Lemanual
  • Lemanual
Is it D :O x+y/x-y?
jigglypuff314
  • jigglypuff314
look at the order in the numerator that I got try again
Lemanual
  • Lemanual
Awww V_V
Lemanual
  • Lemanual
I keep getting x+y/x-y : /
jigglypuff314
  • jigglypuff314
\[(\frac{ 1 }{ x } - \frac{1}{y})*(\frac{xy}{1})\]
jigglypuff314
  • jigglypuff314
\[\frac{ xy }{ x } - \frac{xy}{y}\]
Lemanual
  • Lemanual
Ohhhh
Lemanual
  • Lemanual
So C right?
jigglypuff314
  • jigglypuff314
;-;
Lemanual
  • Lemanual
D:::
Lemanual
  • Lemanual
Meh confused I'm not that good at mathh
jigglypuff314
  • jigglypuff314
reread every one of my previous comments
Lemanual
  • Lemanual
Oh.. My.. God.. :O ;-;
Lemanual
  • Lemanual
Okay.. V_V
brooke2353
  • brooke2353
lmfao
Lemanual
  • Lemanual
I THINK I GOT IT I think<< It's A
jigglypuff314
  • jigglypuff314
good
Lemanual
  • Lemanual
Yay :D
Lemanual
  • Lemanual
Thanks guys again so much I passed my Algebra class now :D I'm all caught up : )
Lemanual
  • Lemanual
Thanks tho for your help really ; ) *wink* *wink* :D
Lemanual
  • Lemanual
Seeya tomorrow guys I will be on everyday probs not weekends tho bye and thanks for the help : )

Looking for something else?

Not the answer you are looking for? Search for more explanations.