anonymous
  • anonymous
HELP! Multiplying and Dividing with Mixed Numbers
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
4 and 2/7 x 2 and 1/5
anonymous
  • anonymous
@GabeBae
benlindquist
  • benlindquist
this is all

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anonymous
  • anonymous
i have 3 others
anonymous
  • anonymous
i have mentaly unable to do ,math with out help
anonymous
  • anonymous
sorry the text looks bad im gettimg used to a new kayboard
benlindquist
  • benlindquist
ok
benlindquist
  • benlindquist
4 and 2/7
anonymous
  • anonymous
can ya help me?
benlindquist
  • benlindquist
what are you wanting to ask?
anonymous
  • anonymous
what does it eaqual i, lost
benlindquist
  • benlindquist
are you trying to make these improper fractions.
anonymous
  • anonymous
mixed number
benlindquist
  • benlindquist
4 and 2/7 x 2 and 1/5. this is what you want to multiply
anonymous
  • anonymous
yes
benlindquist
  • benlindquist
|dw:1449242749980:dw|
anonymous
  • anonymous
thats the think im lost on how to solve it
benlindquist
  • benlindquist
change them into improper fractions
benlindquist
  • benlindquist
|dw:1449242869990:dw|
anonymous
  • anonymous
oh i was trying was trying to solve that btw but thanks now what
benlindquist
  • benlindquist
multiply it
anonymous
  • anonymous
29 x 11 and 7 x 5 '
benlindquist
  • benlindquist
yes
anonymous
  • anonymous
319/35/
benlindquist
  • benlindquist
can you reduce it?
anonymous
  • anonymous
uhhhhh idk
benlindquist
  • benlindquist
try
anonymous
  • anonymous
no
benlindquist
  • benlindquist
9.11428571429
anonymous
  • anonymous
that counts???
benlindquist
  • benlindquist
find your place look next door, 5 or greater add one more, all digits in front stay the same, all digits behind 0 remain.
benlindquist
  • benlindquist
medal please
anonymous
  • anonymous
i dont understand
benlindquist
  • benlindquist
read please, what i just told you
benlindquist
  • benlindquist
i have to go soon, if you want i can help you later.
anonymous
  • anonymous
ok
benlindquist
  • benlindquist
you can just try to look on other sites for help
benlindquist
  • benlindquist
if that ever helps

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