Howard-Wolowitz
  • Howard-Wolowitz
Graphing and residual plot question: Show all work
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Howard-Wolowitz
  • Howard-Wolowitz
1 Attachment
xMissAlyCatx
  • xMissAlyCatx
Well you can tell just by the table that the association is positive..
Howard-Wolowitz
  • Howard-Wolowitz
ok so we can agree 6. is positive

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

xMissAlyCatx
  • xMissAlyCatx
Yes.
xMissAlyCatx
  • xMissAlyCatx
I can guide you on finding the correlation, but I can't tell you the answer. What you want to do is find the mean (average) of x and y. Once you have your mean of your "x" values you will subtract the mean from every individual x-value that you have.. For example, if your x-values were 1 2 and 3, the average of those is 2, so you would do (1-2) (2-2) (3-2) etc..
xMissAlyCatx
  • xMissAlyCatx
Use this as a guide..
1 Attachment
Howard-Wolowitz
  • Howard-Wolowitz
ok I see, but I dont see what to caluucate
xMissAlyCatx
  • xMissAlyCatx
And this is your scatterplot..
1 Attachment
xMissAlyCatx
  • xMissAlyCatx
What do you mean? You calculate the numbers in your table..
Howard-Wolowitz
  • Howard-Wolowitz
I know but how do you know what to do them by?
Howard-Wolowitz
  • Howard-Wolowitz
hmm maybe its the operations
xMissAlyCatx
  • xMissAlyCatx
Well like I said earlier, find your average of x and then average of y.. your average of x is 1.83 your average of y is 2.86 Now you will subtract your average of x from every x-value.. (.3 - 1.83), (.85 - 1.83), (1.50 - 1.83), (2.50 - 1.83), (4.0 - 1.83) and solve those.. so then do the same for y..
xMissAlyCatx
  • xMissAlyCatx
(.8 - 2.86), (2 - 2.86), (2.5 - 2.86), (3 - 2.86), (6 - 2.86) and solve..
Howard-Wolowitz
  • Howard-Wolowitz
ok give me a second
xMissAlyCatx
  • xMissAlyCatx
Tell me what you get for the x values, then the y when you get them.
Howard-Wolowitz
  • Howard-Wolowitz
-1.53 , -0.98 , -0.33 , 0.67 , 2.17
Howard-Wolowitz
  • Howard-Wolowitz
-2.06 , -0.86 , -0.36 , 0.14 , 3.14
xMissAlyCatx
  • xMissAlyCatx
Alright, good. Now what you need to do next is multiply your x and y values with each other.. so -2.06(1.53)= ? -.86(-.98)=? -.36(-.33)=? .14(.67)=? 3.14(2.17)=?
xMissAlyCatx
  • xMissAlyCatx
you will also square your x and y's .. so.. -1.53 squared =? -.98 squared =? and so on, but like I said do it for x and y
Howard-Wolowitz
  • Howard-Wolowitz
-3.1518 , 0.8428 , 0.1188 , 0.0938 , 6.8138
xMissAlyCatx
  • xMissAlyCatx
Now add those up ^ and tell me the final sum of them. And that will be one step out of the way for a moment. (sorry I know it is a lot of work)
Howard-Wolowitz
  • Howard-Wolowitz
4.7174
xMissAlyCatx
  • xMissAlyCatx
Alrightey. Now go ahead and square your x and y's and then add all the x's together then add all the y's together and tell me what you get.. (almost done!)
xMissAlyCatx
  • xMissAlyCatx
That's for x, correct?
xMissAlyCatx
  • xMissAlyCatx
What isn't?
Howard-Wolowitz
  • Howard-Wolowitz
8.42 isnt right
xMissAlyCatx
  • xMissAlyCatx
Let me grab my calculator and work out the x's and y's. Just go ahead and try the y's and I will check it. :P
Howard-Wolowitz
  • Howard-Wolowitz
ok
xMissAlyCatx
  • xMissAlyCatx
I got 6.4294 for the x's..
Howard-Wolowitz
  • Howard-Wolowitz
i am getting undefiend for y and x
xMissAlyCatx
  • xMissAlyCatx
You may be entering them wrong.. I also solved the y's and got 4.7664 So let's just go on from there..
xMissAlyCatx
  • xMissAlyCatx
So now you have.. 4.7174 which is what you got from multiplying x(y) 's 6.4294 from squaring the x's & 4.7664 from squaring the y's What you will do next is add up all three of those numbers..
xMissAlyCatx
  • xMissAlyCatx
So tell me what you get when you add them.
xMissAlyCatx
  • xMissAlyCatx
@Howard-Wolowitz still there? c:
Howard-Wolowitz
  • Howard-Wolowitz
yes im just thinking about how to do it
xMissAlyCatx
  • xMissAlyCatx
Just add up 4.7174 + 6.4294 + 4.7664
xMissAlyCatx
  • xMissAlyCatx
When you add them up you get 15.9132
Howard-Wolowitz
  • Howard-Wolowitz
15.9132
xMissAlyCatx
  • xMissAlyCatx
Yes.. One more step and you're pretty much done!
Howard-Wolowitz
  • Howard-Wolowitz
Bazinga
xMissAlyCatx
  • xMissAlyCatx
|dw:1449246599833:dw|
Howard-Wolowitz
  • Howard-Wolowitz
ok let me solve this
xMissAlyCatx
  • xMissAlyCatx
Yes, whatever you get from this answer will be your correlation :P
xMissAlyCatx
  • xMissAlyCatx
I got 2.8746 So, what you can conclude from this correlation, is since it is greater than one, it would be a strong positive correlation. :)
Howard-Wolowitz
  • Howard-Wolowitz
7. 2.8746 8. what you can conclude from this correlation, is since it is greater than one, it would be a strong positive correlation
xMissAlyCatx
  • xMissAlyCatx
Precisely.

Looking for something else?

Not the answer you are looking for? Search for more explanations.