anonymous
  • anonymous
What is the remainder when (x3 − 4x2 − 12x + 9) is divided by (x + 2)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
- 2 - 6 - 9 - 12
anonymous
  • anonymous
sorry idk the answer but i just wanted to say i love your profile pic
anonymous
  • anonymous
So Off topic

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mathmale
  • mathmale
Among the several methods you could use to find the answer here, are synthetic division and long division. With which would you prefer to begin?
anonymous
  • anonymous
Which is easier to understand?
mathmale
  • mathmale
Actually, I'm asking you which one you understand better.
anonymous
  • anonymous
Long division I guess.
mathmale
  • mathmale
Use the Draw utility if possible. Set up long division like this: (x3 − 4x2 − 12x + 9) is divided by (x + 2|dw:1449257088419:dw|
mathmale
  • mathmale
|dw:1449257152778:dw|
anonymous
  • anonymous
I forget how to do this. Can you remind me how? I'm not asking for the answer; just a bit of a refresher.
mathmale
  • mathmale
What is the value of \[\frac{ x^3 }{ x }? Hint: identify. and. then. subtract. exponents.\]
anonymous
  • anonymous
So... x^2?
mathmale
  • mathmale
yes.
anonymous
  • anonymous
Okay cool. I'm starting to remember a bit.
mathmale
  • mathmale
|dw:1449257323926:dw|
anonymous
  • anonymous
x^3+4?
mathmale
  • mathmale
Your x^3 is fine. The 4 is not. What is the product of x^2 and x+2?
anonymous
  • anonymous
ohhhhhh I multiplied 2 by 2 for some reason. x^3+2x?
anonymous
  • anonymous
I wish I had my notes!! I feel so stupid right now.
anonymous
  • anonymous
omg you left
anonymous
  • anonymous
fine. for anyone here in the future, the answer is 9.
mathmale
  • mathmale
What is the product of x^2 and x+2? x^2 times x is x^3; x^2 times 2 is what? Try again. Pretty please, do NOT share answers (as you have done with 9).
mathmale
  • mathmale
I'm sorry to have stepped out temporarily. I see you're now working on a different problem. If y ou wish, message me if and when you want to continue with me on this discussion. But I will be away for the next few hours.

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