jmoney132
  • jmoney132
Suppose a 14-gram sample of iron is heated from 20.0°C to 25.0°C. The specific heat of iron is 0.11 cal/g°C. How much heat energy was absorbed by the iron? 38.5 cal 7.7 cal 636 cal 69.3 cal
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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whpalmer4
  • whpalmer4
The formula relating heat to specific heat, mass and temperature change is \[Q = m c \Delta T\] You know all of the quantities on the right hand side from the problem statement. \(\Delta T = \text{final temperature} - \text{starting temperature}\)
anonymous
  • anonymous
that is all wrong bruh
whpalmer4
  • whpalmer4
@qveengb Oh, really? Do explain, "bruh"...

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tatianagomezb
  • tatianagomezb
I back @whpalmer4 answer. Because when heated iron absorbs energy, that is released by an unknown source. And using that formula I got 7.7 calories, please correct me if I'm wrong.
anonymous
  • anonymous
um haven't you ever heard of a joke

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