anonymous
  • anonymous
I really need help with Algebra 2 Quadratic Relations and Conic Functions! Identify the conic section, any lines of symmetry, and the domain and range. x=2y^2+5 I need help understand how to do this! I will fan anyone who can help me! 😰
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
umm... I'm not sure. I'll fan you to make up for my failure to help you. :P
anonymous
  • anonymous
@tom982
anonymous
  • anonymous
Firstly, do you know how to identify a conic section?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
A circle is when x^2 and y^2 have the same coefficients, an ellipse is when it's the same sign but different coefficients, and a hyperbola is when it's different signs.
anonymous
  • anonymous
@tom982
anonymous
  • anonymous
@tom982 please help me :(
anonymous
  • anonymous
@CGGURUMANJUNATH
anonymous
  • anonymous
Is that meant to be x^2 in the original equation then? You're talking about x^2 when it's not relevant here.
anonymous
  • anonymous
It says the equation is "x=2y^2+5" and I need to find the conic section, lines of symmetry, and the domain and range @tom982
anonymous
  • anonymous
Okay. Then you're barking up the wrong tree with x^2. Read this: http://www.ck12.org/book/CK-12-Algebra-II-with-Trigonometry-Concepts/section/10.11/ Can you classify it now?
anonymous
  • anonymous
Hyperbola?
anonymous
  • anonymous
A conic is of the form \(Ax^2+Bxy+Cy^2+Dx+Ey+F=0\). Rearranging yours into this form we get: \(2y^2-x+5=0\). This gives us our constants \(A=0\), \(B=0\), \(C=2\)\, \(D=-1\), \(E=0\) and \(F=5\). The discriminant is \(B^2-4AC\) and in this case it is \(0^2-4\times0\times2=0\). As the discriminant is zero, what does this say about our conic? Refer to the page I linked you to.
anonymous
  • anonymous
Ah so a parabola
anonymous
  • anonymous
Exactly, well done. Parabolas are symmetric about the x-axis whenever (x,y)=(x,-y) which we can easily check: \(x=2(-y)^2+5=2y^2+5\) as required. Hence the x-axis (the line y=0) is the only line of symmetry for this parabola. Can you find the domain and range?
anonymous
  • anonymous
Domain: -5<=x<=5 Range: -5<=y<=5?
anonymous
  • anonymous
Why have you restricted the domain? What's wrong with using -6? \(x=2(-6)^2+5=77\)
anonymous
  • anonymous
Wait how did you get that???
anonymous
  • anonymous
Ah sorry I misread what you said, but you're still wrong. Your function is written abnormally: \(f(y)=x\) so our domain is for y and the range is for x. There are no numbers we can't put into this equation so the domain is \(y \in \mathbb{R} \). What numbers can we get out of it?

Looking for something else?

Not the answer you are looking for? Search for more explanations.