Hayhayz
  • Hayhayz
Which equation represents the vertical asymptote of the graph? http://prntscr.com/9acofx
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Hayhayz
  • Hayhayz
@malcolmmcswain
malcolmmcswain
  • malcolmmcswain
I can't see it, can you upload it as an attachment?
Hayhayz
  • Hayhayz
alright hold on

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Hayhayz
  • Hayhayz
1 Attachment
malcolmmcswain
  • malcolmmcswain
Ok, so do you know what an asymptote is?
Hayhayz
  • Hayhayz
imaginary line on a graph that a function or equation approaches more and more closely
malcolmmcswain
  • malcolmmcswain
Correct. So, what is your guess?
Hayhayz
  • Hayhayz
0?
malcolmmcswain
  • malcolmmcswain
Ok, do you know how to find limits?
Hayhayz
  • Hayhayz
choices= x=-8 y=-8 x=0 y=0
Hayhayz
  • Hayhayz
no
malcolmmcswain
  • malcolmmcswain
What is the limit as x approaches 8 from the negative side?
Hayhayz
  • Hayhayz
umm how do find a limit?
malcolmmcswain
  • malcolmmcswain
In other words, what value does it seem to be approaching?
malcolmmcswain
  • malcolmmcswain
So, as x gets closer and closer to 8, y gets higher and higher, right? So, our limit is infinity :)
Hayhayz
  • Hayhayz
oooh okay
malcolmmcswain
  • malcolmmcswain
Ok, but wait.
malcolmmcswain
  • malcolmmcswain
So, using that, we can deduce what?
malcolmmcswain
  • malcolmmcswain
Also, I made a mistake. x is approaching -8
malcolmmcswain
  • malcolmmcswain
So, the answer is...
malcolmmcswain
  • malcolmmcswain
when y = infinity, -insert answer-
Hayhayz
  • Hayhayz
wait so how does the limit help find the vertical asymptotes? cuz in my lesson it says the location of a vertical asymptote is found by setting the denominator of a simplified function equal to 0 solving for x but since theres no equation thats why im confused and i have no idea lol
malcolmmcswain
  • malcolmmcswain
That's another way to do it, but I find limits easier.
Hayhayz
  • Hayhayz
so x=-8?
malcolmmcswain
  • malcolmmcswain
Correct :)
Hayhayz
  • Hayhayz
Thank you mal :)
malcolmmcswain
  • malcolmmcswain
And the horizontal asymptote would be...?
malcolmmcswain
  • malcolmmcswain
No problem :D

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