Abmon98
  • Abmon98
Four identical spring each of spring constant k, are connected both in series and parallel as shown in V).
Physics
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SOLVED
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schrodinger
  • schrodinger
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Abmon98
  • Abmon98
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Abmon98
  • Abmon98
I know that the springs constant in series is given by 1/k=1/k+1/k=1/2k while in parallel its given by k=k+k=2k but how can i obtain k effective for all 4 springs
IrishBoy123
  • IrishBoy123
combine the 2 hat are in parallel first into one equivalent spring then you have three in series, so combine those 3

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Abmon98
  • Abmon98
i still dont get the logic behind why we are doing this?
Abmon98
  • Abmon98
do we treat the 4 spring as if they are a single one?
IrishBoy123
  • IrishBoy123
you have a rule for combining springs in series, and another rule for combining springs in parallel. so use the latter rule first to combine those two parallel springs int an euivalent |dw:1449267869078:dw| the use the first rule to combine the 3 springs that in series
Abmon98
  • Abmon98
the sum of spring constant in parallel is 2k while in series the sum is 1/2k so should it be 1/2+0.5k=0.4k
IrishBoy123
  • IrishBoy123
abmon let me see if i can check your working. a minute :-)
IrishBoy123
  • IrishBoy123
the parallel ones combine to a single spring of constant 2k. you got that in series we have therefore |dw:1449269095756:dw| and \(\dfrac{1}{K} = \dfrac{1}{k} + \dfrac{1}{2k} + \dfrac{1}{k} = \dfrac{5}{2k}\) \(K = 0.4 k\) 👍
Abmon98
  • Abmon98
Thanks for your help.

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