DezAndAlf42714
  • DezAndAlf42714
Ok so I tried this question on my own and got 31 1/4 but it says im not right any help pls? I tried everything but nothing is working. I know you are supposed to work backwards but I cant find an answer. Jake's band played songs at three different parties. At the first party they played one-fifth as long as they did at the second party, which was one and one-fourth as long as the third party. If they played for 5 minutes at the first party, how many minutes did they play at the third party? Select one: A. twenty minutes B. twenty-six and one-fourth minutes C. twenty-eight minutes
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
you still there?
DezAndAlf42714
  • DezAndAlf42714
yes
anonymous
  • anonymous
k cool the answer is c

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DezAndAlf42714
  • DezAndAlf42714
ok. can you explain how you got that?
welshfella
  • welshfella
Time at first party = 1/5 x (x = time at "2nd party) 1/5 x = 5 so x = 5 / (1/5) = 25 minutes
DezAndAlf42714
  • DezAndAlf42714
ok thats what I got for the second party. 25 minutes
welshfella
  • welshfella
Now this was 5/4 times as long as the 3rd party So time in 3rd party = 25 / (5/4) = 25 * 4/5 = 20 minutes
DezAndAlf42714
  • DezAndAlf42714
Oooooh ok!! Thanks a bunch!!!
welshfella
  • welshfella
Yw

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