anonymous
  • anonymous
Simplify 9 over quantity of 3 minus 2 i
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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AlexandervonHumboldt2
  • AlexandervonHumboldt2
is your problem \[\frac{ 9 }{ 3-2i }?\]
anonymous
  • anonymous
Yes
AlexandervonHumboldt2
  • AlexandervonHumboldt2
mutlpy by a congugate: conngugete of 3-2i=3+2i

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DanJS
  • DanJS
you mean put it into the complex number form?
AlexandervonHumboldt2
  • AlexandervonHumboldt2
\[\frac{ 9 }{ 3-2i }*\frac{ 3+2i }{ 3+2i}=\frac{ 9*(3+2i) }{ 3^2-(2i)^2 }=simplify\]
AlexandervonHumboldt2
  • AlexandervonHumboldt2
do you need to rationolize the denominator? or what? yeah
anonymous
  • anonymous
5/5 = 40/ 5? Is that correct
DanJS
  • DanJS
yeah i^2=-1 put that into the complex number form prolly a + b*i
DanJS
  • DanJS
(27+18i) / (9 - 4(-1)) 27/13 + (18/13) *i
anonymous
  • anonymous
The options are Simplify 9 over quantity of 3 minus 2 i. quantity of negative 27 minus 18 i over 13 9 i over quantity of 2 plus 3 i quantity of 27 plus 18 i over 5 quantity of 27 plus 18 i over 13
AlexandervonHumboldt2
  • AlexandervonHumboldt2
hint: \[\frac{ 27 }{ 13 }+\frac{ 18 }{ 13 }i=\frac{ 27+18i }{ 13 }\]
anonymous
  • anonymous
I'm trying to figure it out
anonymous
  • anonymous
How did you get 13?

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