anonymous
  • anonymous
help !!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
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Nnesha
  • Nnesha
use the p/q method where \[\large\rm \frac{ p }{ q}= \frac{\pm ~~all~factors ~of~constant~term}{\pm~~all~factors ~of ~leading ~coefficient }\]
anonymous
  • anonymous
the leading coefficient is 8 and 10 right?

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Nnesha
  • Nnesha
there should be only one leading coefficient coefficient of the highest degree variable
anonymous
  • anonymous
10?
Nnesha
  • Nnesha
what's the highest degree (exponent ) ??
anonymous
  • anonymous
8 sorry
Nnesha
  • Nnesha
yes correct write all factors of 8 and factors of constant term
anonymous
  • anonymous
3x^4+10x^3-11x^2-10x / 8?
Nnesha
  • Nnesha
no. what's the constant term in that function ?
anonymous
  • anonymous
x?
Nnesha
  • Nnesha
that's the variable what would be the leading coefficient and constant term? here is an example \[4x^2+3x+9\] 4 is leading coefficient(coefficient of highest degree variable ) cosntant term is 9( number without any variable )
Nnesha
  • Nnesha
constant*
anonymous
  • anonymous
8 is the constant
Nnesha
  • Nnesha
correct and leading coefficient is ?
anonymous
  • anonymous
11x^2
Nnesha
  • Nnesha
what's the highest exponent in that function ? if u look at my example it was 2 so that's how leading coefficient was 4 \[\large \rm Ax^5+Bx^3+C\]in this example highest exponent is 5 leading coefficient is `A`
anonymous
  • anonymous
3x^4
Nnesha
  • Nnesha
that's the term where just 3 is leading coefficient and now what are the factors of 8 and 3 ?
jim_thompson5910
  • jim_thompson5910
@Nnesha is correct. Here is a slightly different way to look at it
anonymous
  • anonymous
you divide 8/3?
anonymous
  • anonymous
question (not to interrupt) does not ask for the "possible" rational zeros, it asks for the zeros
Nnesha
  • Nnesha
no divide factors of 8 by the factors of of 3 i know they r looking for real zero so she can just graph it
anonymous
  • anonymous
it is not necessary to list all possible rational zeros of this, in fact it is mostly a waste of time you want to find the actual zeros, not the possible rational ones, as there are many
anonymous
  • anonymous
unless you want to make a to see which ones to check
anonymous
  • anonymous
"make a list"
jim_thompson5910
  • jim_thompson5910
@satellite73 the idea is to generate all the possible rational roots then you check each possible root in f(x). If f(x) = 0, then you have a true actual root it might be easier just to go through your answer choices
anonymous
  • anonymous
i would certainly say so!!
anonymous
  • anonymous
huh?
anonymous
  • anonymous
you have choices right? check which ones work
anonymous
  • anonymous
how do i check?
anonymous
  • anonymous
plug in the number
anonymous
  • anonymous
see if you get zero
anonymous
  • anonymous
?
Nnesha
  • Nnesha
|dw:1449286024847:dw| zeros (or x-intercept ) point when graph intersect the x-axis when y=0 so you can substitute given points for x if you get 0 as final answer then that number would be the zero
anonymous
  • anonymous
\[f(1)=3+10-11-10+8=0\] got one on the first try
anonymous
  • anonymous
zeros mean the number that you plug in to get zero out
anonymous
  • anonymous
so if \[f(1)=0\] then "1 is a zero of f"
anonymous
  • anonymous
=0
anonymous
  • anonymous
plug in the numbers, see which give zero that is all
anonymous
  • anonymous
i dont get it i dont know what to plug in
jim_thompson5910
  • jim_thompson5910
Here's one way to generate all the possible rational roots |dw:1449286106549:dw| to fill out the table, you compute p/q eg: first row, first column = p/q = 1/1 = 1 first row, second column = p/q = 2/1 = 2 etc etc once the table is filled out, you just put plus/minus in front of each possible root
jim_thompson5910
  • jim_thompson5910
sorry I mixed up the two, I meant to say q/p
jim_thompson5910
  • jim_thompson5910
@LegendaryNikki if you replaced every x with -1, what result would you get?
anonymous
  • anonymous
i dont know
Nnesha
  • Nnesha
what would you do to know ?? :=) substitute all x for -1 then simplify what would u get ?
anonymous
  • anonymous
ok hold on
anonymous
  • anonymous
f(x)=0
Nnesha
  • Nnesha
okay now try 2/3 substitute all x for 2/3 and remember the highest exponent represents the number of solutions(zeros )(including complex , imaginary)
anonymous
  • anonymous
0
Nnesha
  • Nnesha
look at the original equation for a sec what's the highest exponent ?
anonymous
  • anonymous
im confused
Nnesha
  • Nnesha
to be honest i don't really like the way *testing each option* it wouldn't work for all questions well anyways what you don't understand ? what r you confused about ?
anonymous
  • anonymous
remember the highest exponent represents the number of solutions(zeros )(including complex , imaginary)
Nnesha
  • Nnesha
okay what's the highest exponent in that function ??
anonymous
  • anonymous
3
Nnesha
  • Nnesha
that's the leading coefficient i'm asking about exponent
Nnesha
  • Nnesha
\[\large \rm Ax^5+Bx^3+C\] in this example 5 is the highest exponent so there should be 5 solutions

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