anonymous
  • anonymous
anyone here! i need help use long division. state the quotient,q(x),and remainder,r(x 21x^4+24x^3+2x^2/3x^2+2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Nnesha
  • Nnesha
you ready ?
anonymous
  • anonymous
yes please help
Nnesha
  • Nnesha
for long division 5 steps) \(\huge\color{green}{{1:}}\) Divide the first terms \(\huge\color{green}{{2:}}\) multiply(distribute) \(\huge\color{green}{{3:}}\) subtract all terms \(\huge\color{green}{{4:}}\) carry down \(\huge\color{green}{{5:}}\) repeat |dw:1449287936788:dw|

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anonymous
  • anonymous
|dw:1449288077668:dw|
anonymous
  • anonymous
help me with the rest please
Nnesha
  • Nnesha
alright good not just keep the 24x^3 term that down |dw:1449288417985:dw| and then repeat the pattern!
Nnesha
  • Nnesha
wait and since we have to write in descending order so we should put 0x for the last term it's not in the given function but wee know it's decreasing by one x^4,x^3,x^2,x^1,x^0
anonymous
  • anonymous
|dw:1449288524045:dw|
Nnesha
  • Nnesha
|dw:1449288605677:dw| like this
Nnesha
  • Nnesha
|dw:1449288626139:dw| it should be x^2
Nnesha
  • Nnesha
2x^2-14x^2=-12x^2 make sense ? do you understand that ? and 0x+0 term ?? any question :=))
anonymous
  • anonymous
no i dont get it
Nnesha
  • Nnesha
which one ? do you know 2x^2-14x^2 =-12x^2 when we combine like terms we should just( subtract/add) the coefficient and we keep the variable as it s
anonymous
  • anonymous
ok i got this one thanks
anonymous
  • anonymous
:)
Nnesha
  • Nnesha
alright so for 0x+0 we should write the function in descending order doesn't matter if they give u or not all terms we should write it as highest to lowest exponent form so for this function we just have x^4 term x^3 term x^2 term but we know it's decreasing by one so for x^1 term we should put 0x^1 (anything times 0 is just 0 ) that's how x^1 term is invisible in the original equation
anonymous
  • anonymous
yup thanks
Nnesha
  • Nnesha
|dw:1449289768985:dw| now just repeat the pattern again

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