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The equations of two adjacent sides of a rhombus are: y = 2x +4 , and y = -(1/3)x + 4
If 12,0 is one vertex and all vertices have positive coordinates, find the coordinates of the other 3 vertices.
I figured out that one of the other vertices is 0,4 but I'm stuck on finding the other two, any hints would be appreciated!
Thanks in advance!
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and technically all the vertex do NOT have positive coords, since 0 is neither positive nor negative.
Finding the mistakes in the geometry textbooks, nice @amistre64
How should they have said that, differently then? Above the x axis?
12,0 is on the x axis so no...
non-negative solutions would have been accurate.
as for a method of solution.
center a circle at 0,4 with a radius the length from 0,4 to 12,0 ..
x^2 + (y-4)^2 =160
assuming a rhombus has 4 equal sides, the lines will intersect at a third vertex.
then crossing lines at the knew points, should find the other vertex ...
Sorry for the delay in response!
Thanks for the tips! I never thought of using a circle, but I think that will help. I should be able to solve this if I put my head down.
Thanks again! c: