Jadedry
  • Jadedry
Graphing question!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Jadedry
  • Jadedry
The equations of two adjacent sides of a rhombus are: y = 2x +4 , and y = -(1/3)x + 4 If 12,0 is one vertex and all vertices have positive coordinates, find the coordinates of the other 3 vertices. I figured out that one of the other vertices is 0,4 but I'm stuck on finding the other two, any hints would be appreciated! Thanks in advance!
ShadowLegendX
  • ShadowLegendX
I lost my Geometry notebook e-e
amistre64
  • amistre64
isnt a rhombus a squashed square?

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amistre64
  • amistre64
|dw:1449334213255:dw|
amistre64
  • amistre64
and technically all the vertex do NOT have positive coords, since 0 is neither positive nor negative.
ShadowLegendX
  • ShadowLegendX
Finding the mistakes in the geometry textbooks, nice @amistre64 How should they have said that, differently then? Above the x axis?
amistre64
  • amistre64
12,0 is on the x axis so no... non-negative solutions would have been accurate.
amistre64
  • amistre64
as for a method of solution. center a circle at 0,4 with a radius the length from 0,4 to 12,0 .. x^2 + (y-4)^2 =160 assuming a rhombus has 4 equal sides, the lines will intersect at a third vertex. then crossing lines at the knew points, should find the other vertex ...
Jadedry
  • Jadedry
@Amistre64 Sorry for the delay in response! Thanks for the tips! I never thought of using a circle, but I think that will help. I should be able to solve this if I put my head down. Thanks again! c:

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