anonymous
  • anonymous
Heelp A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey results for the first-, second-, and third-period classes are as follows: First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3, 0 Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2 Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3 Which is the best measure of center for second period and why? Mean, because there are no outliers that affect the center Median, because there is 1 outlier that affects the center Interquartile
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@ganeshie8 @dan815 @Michele_Laino @pooja195 @Luigi0210 @ganeshie8 @nincompoop @AlexandervonHumboldt2
Michele_Laino
  • Michele_Laino
I think that we have to compute the mean value of the values of the second period
anonymous
  • anonymous
I'm really lost and I really need an A on this please help mer

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anonymous
  • anonymous
Mean, because there are no outliers that affect the center Median, because there is 1 outlier that affects the center Interquartile range, because there is 1 outlier that affects the center Standard deviation, because there are no outliers that affect the center
anonymous
  • anonymous
Those are the answers
Michele_Laino
  • Michele_Laino
when I was at university, at first laboratory physics course, usually, I neglected the outliers, and subsequently I computed the mean value, namely after deleting or rejecting all outliers. Nevertheless, please ask to another helper
anonymous
  • anonymous
So you don't know the answer?
welshfella
  • welshfella
Statistucs is not my forte by I would say the mean is best measure of center
anonymous
  • anonymous
So which option do you suggest?
anonymous
  • anonymous
3

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