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question is incomplete
Its not..Its exactly what it says...
Its Direct Variation
it is complete @dayakar
y:15 16:30 find y?
x ,y are in direct variation x1/y1 = x2/y2
Ummm...I dont understand..
15/16 = 30/y simplify it
when x=30, then y=16 if x=15, then what is the value of y that is, 30 is to 16, as 15 is to what (y)? to answer that, we do y1/x1 = y/x2 and solve for y y1=16 x1=30 x2=15 so our equation resolves to 16/30=y/15 16*15/30 = y solve for y
in this ratio of x and y = constant
@sasogeek my approach is also correct,i will show u
you approach doesn't answer the question... it is a solution, but not a solution to the problem we have here...
that makes no sense, because it's not an exponential function. it's linear. when x is 30, y is 16. how is it that when x is 15, y is 32?
you got it wrong from the very beginning. it's supposed to be 16:30, and not 15:16....
for x x1 = 30 x2 = 15 = 30/2 for y y1 = 16 y2 = 8 = 16/2 the constant is 2, and it is a multiplier.... it's a linear function
@sasogeek plz ,can u show your work
@sasogeek x,y are in direct variation you did it indirect variation plz check again
when x increases, y increases and when x decreases, y decreases 16:30 = y: 15 => 16/30 = y/15 16*15 / 30 = y 240 / 30 = y 8 = y y= 8 therefore, 16:30 = 8:15 0.53 = 0.53 (8*2) : (15*2) = 8:15
given x=15 and y= 16 if x = 30 [increased] y=32 [increased]
you got it all twisted according to the question, given x=30 and y=16 then if x=15, y = what? it has to be less than 16 because x has decreased, the value of y must also decrease
@jabez177 ,plz,do u explain whose approach is correct
You both are confusing me....
@mathmale Can you help please?
@Angel360 , i am sorry, wait some time for a good explantion
@CGGURUMANJUNATH Please help me!
we can agree to the fact that there must be some relation between x and y like in equation form whatever the equation is(straight line, circle, ellipse.,etc) we can write it in this form-> \(ax^2+by^2+2hxy+2gx+2fy+c=0\) here only x and y are variables rest all are constants which can't be all 0 at the same time we need to know some more information in order to figure out what the relation is exactly so its incomplete