iwanttogotostanford
  • iwanttogotostanford
NE
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
iwanttogotostanford
  • iwanttogotostanford
i got: 5 x cubed over 4 y to the fourth power
iwanttogotostanford
  • iwanttogotostanford
@iYuko is this right please?
iwanttogotostanford
  • iwanttogotostanford
@zepdrix

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zepdrix
  • zepdrix
I can't understand the wording of your question, it's so ambiguous :( `15 x to the eighth power over 24 y to the fifth power` divided by 4 x to the fourth power over 8 squared So this is a fraction, divided by a fraction, is the eight power being applied to the 15 as well? Or only the x?
iwanttogotostanford
  • iwanttogotostanford
it is 15x^8 and yes it is a fraction divided by a fraction
zepdrix
  • zepdrix
Like this?\[\large\rm \frac{15x^8}{24y^5}\div\frac{4x^4}{8^2}\]
iwanttogotostanford
  • iwanttogotostanford
exaactly
zepdrix
  • zepdrix
Recall that dividing by a fraction is the same as multiplying by the reciprocal. So we have,\[\large\rm \frac{15x^8}{24y^5}\times\frac{8^2}{4x^4}\]
zepdrix
  • zepdrix
Let's try to cancel some stuff out. We have 8 x's multiplying in the top, 4 x's multiplying in the bottom. So we can divide out 4 of those x's, leaving us with x^4 in the top, yes?
zepdrix
  • zepdrix
\[\large\rm \frac{15x^{\cancel84}}{24y^5}\times\frac{8^2}{4\cancel{x^4}}\]
iwanttogotostanford
  • iwanttogotostanford
ok!
zepdrix
  • zepdrix
\[\large\rm \frac{15x^4}{24y^5}\times\frac{8^2}{4}\]
iwanttogotostanford
  • iwanttogotostanford
i got 5x^3/4y^4 as my final answer but thats prob not right
iwanttogotostanford
  • iwanttogotostanford
@zepdrix
zepdrix
  • zepdrix
Hmm ya that seems a little off...
iwanttogotostanford
  • iwanttogotostanford
please help haha
zepdrix
  • zepdrix
Let's break up the numbers a little bit, look for common factors. 15 is 5x3 24 is 8x3\[\large\rm \frac{5\cdot3x^4}{8\cdot3y^5}\times\frac{8^2}{4}\]
iwanttogotostanford
  • iwanttogotostanford
ah ok i see
mathmale
  • mathmale
You'd be much better off if you would please present your expressions in mathematical terms, and not in words. That would have avoided our going off the point in our previous discussion.
iwanttogotostanford
  • iwanttogotostanford
ok @mathmale @zepdrix is helping me already, thanks
zepdrix
  • zepdrix
lol XD
iwanttogotostanford
  • iwanttogotostanford
ok so what do we do from there? @zepdrix
zepdrix
  • zepdrix
I guess we can break down the numbers in the second fraction a little further as well, rewrite 8^2 as 8*8,\[\large\rm \frac{5\cdot3x^4}{8\cdot3y^5}\times\frac{8\cdot8}{4}\]and then rewrite that 8 as 4*2,\[\large\rm \frac{5\cdot3x^4}{8\cdot3y^5}\times\frac{8\cdot4\cdot2}{4}\]And now cancel out things which appear in both the numerator and denominator.
zepdrix
  • zepdrix
Looks like the 3's will cancel out, ya? What else?
iwanttogotostanford
  • iwanttogotostanford
yes, and the 4s
zepdrix
  • zepdrix
and the 8's, ya?
iwanttogotostanford
  • iwanttogotostanford
yup
zepdrix
  • zepdrix
So, ya, cancel your stuff,\[\large\rm \frac{5\cdot3x^4}{8\cdot3y^5}\times\frac{8\cdot4\cdot2}{4}\quad=\frac{5x^4}{y^5}\cdot\frac{2}{1}\]
iwanttogotostanford
  • iwanttogotostanford
yes!
iwanttogotostanford
  • iwanttogotostanford
an dhats all?
zepdrix
  • zepdrix
Well, multiply the 5 and 2, but yes.
iwanttogotostanford
  • iwanttogotostanford
so, i would get : 5 x to the fourth power over 4 y cubed correct?
iwanttogotostanford
  • iwanttogotostanford
@zepdrix
zepdrix
  • zepdrix
No, you would get 10 x to the fourth power over y to the fifth power
iwanttogotostanford
  • iwanttogotostanford
but these are the only anew choices: 4 y cubed over 5 x to the fourth power 4 y to the fourth power over 5 x cubed 5 x to the fourth power over 4 y cubed 5 x cubed over 4 y to the fourth power
iwanttogotostanford
  • iwanttogotostanford
@zepdrix
iwanttogotostanford
  • iwanttogotostanford
@robtobey
AihberKhan
  • AihberKhan
What is the simplified form of 24 y to the fifth power over 15 x to the eighth power divided by 8 y squared over 4 x to the fourth power ? ------------------- \[(24y^5)/(15x^8) / (8y^2)/(4x^4)\] ------ = \[(24y^5)/(15x^8)\] = \[24y^5/8y^2] * [4x^4/15x^8\] = \[3y^3] * (4/15x^4\] = \[y^3 *(4/5x^4)\] = \[(4/5)(y^3/x^4)\]
AihberKhan
  • AihberKhan
Hope this helped! Have a great day! Also a medal would be much appreciated! Just click best response next to my answer. Thank You! @iwanttogotostanford

Looking for something else?

Not the answer you are looking for? Search for more explanations.