anonymous
  • anonymous
Which of the following graphs could represent a 6th-degree polynomial function, with 3 distinct zeros, 1 zero with a multiplicity of 2, 1 zero with a multiplicity of 3, and a negative leading coefficient?
Mathematics
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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mathmale
  • mathmale
A 6th degree poly should give you 6 zeros. Of these 6, 3 must be distinct. This means you'll have exactly 3 points on the horizontal number like where the graph either crosses or touches the horizontal axis. If a zero has a multiplicity of 2, that means the graph will loop either up or down and that its vertex will only touch (not cross) the horiz. axis. If ... a multiplicity of 3, the graph will actually cross the horiz axis at that x-value.
mathmale
  • mathmale
Could you possibly post illustrations of the four graphs that represent possible answers?

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