Fanduekisses
  • Fanduekisses
Who can help me with chemistry? I have final next week and I need help understanding Acid/Base reactions :(
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Kkutie7
  • Kkutie7
I might be able to help depending on your questions.
Fanduekisses
  • Fanduekisses
hi ^_^
Fanduekisses
  • Fanduekisses
for example: Write the net reaction for: \[HNO_{3 (aq)}+KOH_{(aq)}\rightarrow H_{2}O+KNO_{3(aq)}\]

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Fanduekisses
  • Fanduekisses
I don't even know where to start.
Kkutie7
  • Kkutie7
alright so the basics of acid/base chemistry is a transfer of a proton (H+)
Kkutie7
  • Kkutie7
in your equation the acid is the reactant that gives up a proton and the basic accepts it.
Kkutie7
  • Kkutie7
I'm going to do a little bit of arrow pushing to explain your rxn please don't get intimidated because I doubt you'll need to do this on a acid/base test.
Kkutie7
  • Kkutie7
|dw:1449351454715:dw| here is a representation of the rxn (please let me know if you have an issue understanding what I present)
Fanduekisses
  • Fanduekisses
oh ok yes so far I'm understanding :)
Kkutie7
  • Kkutie7
|dw:1449351608743:dw|
Kkutie7
  • Kkutie7
N is going to have freed up valence electron, as does K, so they bind with each other
Kkutie7
  • Kkutie7
Now that that is explained you have "write the net reaction" I assume you mean net ionic reaction?
Fanduekisses
  • Fanduekisses
yes
Kkutie7
  • Kkutie7
so you start out with an rxn that is balanced as you have here: \[HNO_{3 (aq)}+KOH_{(aq)}\rightarrow H_{2}O+KNO_{3(aq)}\] break all aq apart: \[H+_{(aq )}+NO^{-}_{3 (aq)}+K+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_{2}O_{(l)}+K+_{(aq)}+NO^{-}_{3(aq)}\]
Kkutie7
  • Kkutie7
Now you need to "delete" any spectator ions: \[H+_{(aq )}+OH^{-}_{(aq)}\rightarrow H_{2}O_{(l)}\] this is the net ionic equation =)
Kkutie7
  • Kkutie7
I hope you get it
Fanduekisses
  • Fanduekisses
ohh so it's basically breaking all aq apart then removing everything that didn't change? ohhh cool ^_^
Fanduekisses
  • Fanduekisses
ohh so it's basically breaking all aq apart then removing everything that didn't change? ohhh cool ^_^
Fanduekisses
  • Fanduekisses
And for this one, I think is precipitation. Is it correct? \[Pb(NO_{3})_{2(aq)}+Na_{2}SO_{4(aq)} \rightarrow PbSO_{4(s)} + KHSO_4(aq)\] I get \[Pb^{2+}+SO_{4}^{2-}\rightarrow PbSO_{4(s)}\]
Kkutie7
  • Kkutie7
it is precipitation because PbSO4 is a salt
Kkutie7
  • Kkutie7
let me write it out so you can see: (note: this is what I'm thinking its late here so don't be too confident in my work. \[Pb+N_{2}+O_{6}+Na_{2}+S+O_{4} \rightarrow PbSO_{4(s)} + K+H+S+O_4\] \[Pb+N_{2}+O_{6}+Na_{2}+S \rightarrow PbSO_{4(s)} + K+H+S\] \[Pb+N_{2}+O_{6}+Na_{2} \rightarrow PbSO_{4(s)} + K+H\] just from here I don't see any other ions that can be eliminated. However the net ionic equation has to be balance. I don't have a correct way to explain it but you are correct.

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