anonymous
  • anonymous
The length of a rectangle is 8 in. more than its width. The perimeter is 52 in. What is the length of the rectangle? @pooja195
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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pooja195
  • pooja195
\[\huge~\rm~L=w+8\] The formula for perimeter is \[\huge~\rm~P=2L+2w\] We know that the perimeter is 52in
anonymous
  • anonymous
i dont understand
anonymous
  • anonymous
oh ok

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pooja195
  • pooja195
Let's try an easier approach .-. 2L+2W=52 <---equation for perimeter W=L-8 <---re-arranged equation for length
pooja195
  • pooja195
Basically take equation 2 and plug it in place of w in equation 1 \[\huge~\rm~2L+2(L-8)=52 \] From here solve for L
anonymous
  • anonymous
4L(L-8)=52?
pooja195
  • pooja195
Can you show me the steps you did to get that so i can find your mistake?
anonymous
  • anonymous
i added 2L+2
anonymous
  • anonymous
Solve the following for L, the length : 2( (L-8) + L ) = 52
pooja195
  • pooja195
Ok Start by distributing 2(L−8) 2 x L =2L 2 x -8=?
anonymous
  • anonymous
2x-8= -16?
pooja195
  • pooja195
Good Good so now we have \[\huge~\rm~2L+2L-16=52 \] combine like terms
anonymous
  • anonymous
this is the part that always gets me
pooja195
  • pooja195
Combine the l's together 2+2=?
anonymous
  • anonymous
4L
pooja195
  • pooja195
Good \[\huge~\rm~4L-16=52\] now add 16 to both sides 52+16=?
anonymous
  • anonymous
4L=36
pooja195
  • pooja195
56+12=36?
anonymous
  • anonymous
?
pooja195
  • pooja195
52+16=?
anonymous
  • anonymous
68
pooja195
  • pooja195
4L=68 divide both sides by 4 4/4=1 just L 68/4=?
anonymous
  • anonymous
68/4=17
pooja195
  • pooja195
Good we we have L=17 :)
anonymous
  • anonymous
WOW Thank you
pooja195
  • pooja195
yw ^_^

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