At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
there are two ways to solve it. substitution or elimination. do you have a preference?
but i think substitution would be easier. 2x+3y= -6 x-y=4
you can start by adding y to both sides in the second equation and you'll get ... ?
How do you add both sides?
|dw:1449363994185:dw| since -y+y=0
no. just x=4+y we're not multiplying
So what next?
so now whever you see x in the first eequation you substitute with y+4
So how do you do 2(4 + y)?
do you know how to distribute
ex. a(x+y)= ax +ay
8 + 5y= -6
subtract 8 on both sides. divde by 5 on both sides to solve for y
yes. but it tells you to round to neaerest integer. and that would be -3
to find x, use the second equation. x-y=4 since you know y=-3 just plug that into the equation to solve for x
2x+3y= -6 x-y=4 2x+3y= -6 3x-3y=12 5x=6 x=6/5 x-y=4 6/5-y=4 6/5-4=y 6/5-20/5=-14/5=y
1.2 ... is what?
well, that isn't what I get..
maybe the question is different?
What do you get?
x=6/5 (I showed this) or, =1.2
(but you said x=1)
Please read the instructions for this problem carefully. You are supposed to ESTIMATE the solution by reading off x- and y-values from the given graph. Look for the point at which the 2 lines intersect. At this point, x is close to which integer? y is close to which integer?