anonymous
  • anonymous
Help with Kirchoff nodal analysis
Physics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
Find the voltages at each node using nodal analysis. I just need to get to the 5 equations and 5 unknowns part and I can take it from there.
anonymous
  • anonymous
@amistre64 you good in physics?

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amistre64
  • amistre64
newtonian basics .... nothing much of anything more advanced.
amistre64
  • amistre64
what is nodal analysis?
amistre64
  • amistre64
is V5 a node? what im reading is that it should be 3 or more branches
anonymous
  • anonymous
I'm not entirely sure how to explain it. This is actually for a MATLAB class, using MATLAB to solve the 5 equations and 5 unknowns when you get that far. I had to result in a youtube video to kinda get an idea of what to do but i still dont think im doing it right.
anonymous
  • anonymous
Yeah v5 is a node
anonymous
  • anonymous
http://www.ee.hacettepe.edu.tr/~solen/Matlab/MatLab/Matlab%20-%20Electronics%20and%20Circuit%20Analysis%20using%20Matlab.pdf it starts on page 72
anonymous
  • anonymous
i lied, 70
amistre64
  • amistre64
the direction in or out of a node represents a + or - value ...
anonymous
  • anonymous
right
amistre64
  • amistre64
how do we calculate for the coeffs of v1,v2,v3,etc?
anonymous
  • anonymous
you get a common denominator and move the constants to the other side and combine like terms.
amistre64
  • amistre64
direction to node divided by resitance ... and the -5 is the current defined already for V1
amistre64
  • amistre64
|dw:1449370261362:dw|
amistre64
  • amistre64
(V2 to V1)/10 + (V2 to V3)/40 +(V2 to G)/50 = 0
anonymous
  • anonymous
and then you have to do the same thing for the other two nodes
anonymous
  • anonymous
so you get 3 equations and 3 unknowns in this case
amistre64
  • amistre64
correct
anonymous
  • anonymous
ok now in my problem here's where im confused
anonymous
  • anonymous
at node v5
anonymous
  • anonymous
its v5 to v4 but there's no resistance between them, just a 6A current
amistre64
  • amistre64
the current is already provided yes ... is it coming to the node or going away from it?
anonymous
  • anonymous
its going away from v5 towards v4
amistre64
  • amistre64
your text say current away from a node is positive
anonymous
  • anonymous
|dw:1449370590741:dw|
amistre64
  • amistre64
|dw:1449370649942:dw|
amistre64
  • amistre64
(V5 to G)/8 + 6
anonymous
  • anonymous
do you consider ground a node?
anonymous
  • anonymous
ahh ok
amistre64
  • amistre64
Ground is equal to 0
amistre64
  • amistre64
so (V5)/8 + 6 is our equation
anonymous
  • anonymous
ok so I did do that right
anonymous
  • anonymous
and for node V4. Let me draw real quick
anonymous
  • anonymous
|dw:1449370755485:dw|
anonymous
  • anonymous
-6 + (v4 - v3)/3
anonymous
  • anonymous
?
amistre64
  • amistre64
(V1)/4 + (V1-V3)/2 -3 = 0 3 + (V2-V3)/5 + (V2-V4)/6 = 0 (V3-V1)/2 + (V3-V2)/5 + (V3-V4)/3 -4 = 0 (V4-V2)/6 + (V4-V3)/3 - 6 = 0
anonymous
  • anonymous
and my equation for v4 is correct?
amistre64
  • amistre64
V4 has 3 branches ... -V2, -V3, and -V5 subtract the node it goes to, and divide off the resistance. if the node it goes to is current ... add/subtract it depending in direction
amistre64
  • amistre64
(V4-V2)/6 + (V4-V3)/3 - 6 = 0
anonymous
  • anonymous
ohh i forgot it goes to v2!
anonymous
  • anonymous
Thank you yet again for your help! I wish i could give all the medals to you lol
amistre64
  • amistre64
youre welcome :)
anonymous
  • anonymous
Have a good night!

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