anonymous
  • anonymous
How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?
Chemistry
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@Hayhayz
Hayhayz
  • Hayhayz
oh boy.. this is what I'm doing too and its confusing for me.. are you by any chance in flvs?
anonymous
  • anonymous
Nope.

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More answers

Photon336
  • Photon336
You need to write out the balanced equation first. \[2C_{2}H_{6}+7O_{2} \rightarrow 4CO_{2}+6H_{2}O\]
Photon336
  • Photon336
what this tells us is that 2 moles of ethane react with 7 moles of oxygen gas. we are given 62.3 grams of Oxygen so we need to convert this to moles. We do this by \[(\frac{ mol }{ 32grams_{oxygen gas} })*(62.3grams) =1.9468 =~ 2 moles_{oxygen gas}\]
Photon336
  • Photon336
now that we have 2 moles of oxygen gas we need to figure out how many moles of ethane we need so we multiply this number by the molar ratio. do you know how to do this?
anonymous
  • anonymous
no..
Photon336
  • Photon336
We need to multiply the number of moles of oxygen gas by the molar ratio of oxygen to ethane. \[\frac{ 2C_{2}H_{6} }{ 7O_{2} }*2mol_{Oxygen gas} = 0.57 moles, ethane\]
anonymous
  • anonymous
That's it..?
Photon336
  • Photon336
yes
anonymous
  • anonymous
Thanks!
Photon336
  • Photon336
no problem welcome to Open Study

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