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I got 40 and 40. but it is incorrect
an even amount is cut off the sides, so you get L - 20 for the remaining side (a dimension of the box)
so if i got 40 for my length, its the width will be 20? but i thought that because the square was equal on every side, all sides would be 40.
it is a square, call each side S, the 10x10 corners are cut, removes 20 total from each side S
notice the box , when folded, will have two of the dimensions as S-20, the other is that height, the 10
fold where dotted lines are |dw:1449372130634:dw|
square base S-20 and the height 10
so would i use 10(s-20)
they tell you it is a square first off, the lengh = width
the folded box has V=L*W*H = (S - 20) * (S - 20) * 10
the'Square' cardboard needed has side S = length = width
so (s-20)(s-20)*10 would give you (s^2 -40s+400)*10
yeah, and they tell you that is 64000 cm^3
so what do i do now?
solve 10*(s^2 -40s + 400) = 64000
10(s^2 -40s + 400) =64,000 10s^2-400s+4,000=64,000 10s^2-400s=60,000
that s^2 - 40s + 400 is just more work, 6400 = (S-2)^2 abs(S - 2) = 80
solves to S - 2 = 80 and S-2 = -80 we consider positive values only, a physical length measure
so is that the length or width? 82
I'll use Dan's suggestion: Let the length of one side of the square of cardboard be represented by L. Our job is to find L. If squares that are 10 cm by 10 cm are cut off all four corners of the piece of cardboard, the length of one side of the bottom of the box is then L-2(10cm), or L-20. The volume of the box is given; it is 64,000 cm^3. But there's also a formula for that volume, given in terms of L. It is (L-20)(L-20)(10). Form an equation from this information. Solve it for L. The piece of cardboard must have dimensions L by L cm.
i solved it and got 82 by 82
had some laundry,, 82 looks good
you just have to first divide by 10, then square root, easier than all that expanding stuff
since it is 'square'
but i just typed it in and i got it wrong
do you have to include the unit measurement
o haha, i see
i put in L-2 not 20 in the calculator.. and even typed it a few times, using 20 instead , you get a positive value of 100 cm
same pretty much, 80 + 20 and -80 + 20 real length + measure
Strictly speaking, you can do the math without the dimensions "cm." I prefer to inc lude the dimensions so as not to lose track of what we're measuring. Let the length of one side of the square of cardboard be represented by L. Our job is to find L. If squares that are 10 cm by 10 cm are cut off all four corners of the piece of cardboard, the length of one side of the bottom of the box is then L-2(10cm), or L-20. The volume of the box is given; it is 64,000 cm^3. But there's also a formula for that volume, given in terms of L. It is (L-20)(L-20)(10). Form an equation from this information. Solve it for L. The piece of cardboard must have dimensions L by L cm. For those who don't want to go through all this work, just check out the proposed answer (L=82 cm) in (L-20)(L-20)(10). If the result is 64,000 cm^3, then L=82 cm is correct.
it is incorrect.
used L - 2 as mistypings to solve using 20 , yua get 100 for the + value
@chikennooget : Earlier, y ou typed in :"i solved it and got 82 by 82" Time to do some checking to find out what went wrong. Or, solve (L-20)(L-20)(10)=64000 for L.
i got 272.982
Check that: Does [ (272.982-20)^2 ]^2*10 equal 64000? First you calculated that L=82, then as 272.982. Dan calculated L to be 100. Try L=100. Then go back and check L=272.982. Conculusion?
I have to get off the 'Net now. Good luck!