anonymous
  • anonymous
URGENT PLEASe Describe the changes in molecular geometry and hybridization that take place during the following reactions: • A) BF3 + F− ----> BF4−
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
caozeyuan
  • caozeyuan
sp2 for BF3 because there are 3 bonds, so Boron has a sp3 hybridization and it is trigonal planar. BF4 is sp3 and tetrahedral
anonymous
  • anonymous
but how do you know that ?
caozeyuan
  • caozeyuan
after you do enough question you develop an instinct for hybridization and geometry

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
alrite thanksss soo much
anonymous
  • anonymous
My drawing is on paint and it's a bit confusing, but it shows the hybridization steps. Look at Boron's electron configuration: \[1s^22s^22p^1\] Draw the electron orbitals and fill them out. Your \[1s^2\] orbital and \[2s^2\] orbitals are full, they both have a spin up and spin down electron in them. The \[2p\] orbitals only has 1 electron, which leaves room for five more electrons (bc 2p orbitals have up to 6 electrons in them). Five more electrons means five bonds. But with BF3, you only need three bonds because there are only 3 fluorines. So, you take the two electrons out of your full 2s orbitals and move them into your 2p orbitals. So now, instead of \[2s^2\] you have \[2s^0\] and instead of \[2p^1\] you have \[2p^3\] This is called \[sp^2\] hybridization because you included 1 s orbital and 2 p orbitals in the hybridization. Now there is room for only 3 bonds. Now that you need to add a fourth fluorine, you need to add another bond. So you move the empty s bond up and there is room for an extra two bonds, and this is called \[sp^3\] hybridization because you involved 1 s orbital and 3 p orbitals. Once you move that empty s orbital up, you have room for 2 more bonds. But you only need one more bond, which is why BF3 has that line sticking out of it (because it is representing an additional bond).
anonymous
  • anonymous
1 Attachment

Looking for something else?

Not the answer you are looking for? Search for more explanations.