anonymous
  • anonymous
How do I solve the system? x^2 + xy = 1 xy + y^2 = 3
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
DanJS
  • DanJS
you can maybe solve one of them for either x or y, and put all that in for the variable in the other equation, to reduce to single var
jim_thompson5910
  • jim_thompson5910
Solve for `xy` in either equation. I'm going to pick on the second equation xy + y^2 = 3 xy + y^2-y^2 = 3-y^2 xy = 3-y^2 then plug this into the other equation x^2 + xy = 1 x^2 + 3-y^2 = 1 x^2-y^2 + 3 = 1 x^2-y^2 + 3-3 = 1-3 x^2 - y^2 = -2 This is as far as you can go really. We'd need another equation to figure out what x and y are. In this case, there are infinitely many solutions. Each solution (x,y) lies along a hyperola
DanJS
  • DanJS
plug in (1/2 , 3/2)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

arnavguddu
  • arnavguddu
x.x+xy=x(x+y)=1 xy+y.y=y(x+y)=3 divide first eqn. by second, x/y=1/3 or y=3x now solve 1st eqn by substitution and solve for y, then find x
jim_thompson5910
  • jim_thompson5910
@arnavguddu has the right idea. There will be 2 solutions in the form (x,y)
DanJS
  • DanJS
yeah that is good, y = 1/x - x solving the first equation for the y, and using that, you can get to the end too
DanJS
  • DanJS
the process you did @jim_thompson5910 looks like the same as adding (-1)times the first equation to the other eq does that linear system work for those nonlinear things too
DanJS
  • DanJS
linear sytem solving rules
DanJS
  • DanJS
constant multioplication and adding equations and changing order, linear algebra

Looking for something else?

Not the answer you are looking for? Search for more explanations.