anonymous
  • anonymous
An automobile has a total mass of 1300 kg. It accelerates from rest to 65 km/h in 14 s. Assume each wheel is a uniform 30 kg disk. Find, for the end of the 14 s interval, (a) the rotational kinetic energy of each wheel about its axle, (b) the total kinetic energy of each wheel, and (c) the total kinetic energy of the automobile
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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IrishBoy123
  • IrishBoy123
start like this, for one wheel.... \(T_{rot} = \dfrac{1}{2} I \omega^2 = \dfrac{1}{2} \left( \dfrac{1}{2}mr^2\right) \left( \dfrac{v}{r} \right)^2\) you don't need the wheel's radius
Michele_Laino
  • Michele_Laino
I think that the kinetic \(KE\) energy of a single wheel can be written like below: \[\huge \begin{gathered} KE = \frac{1}{2}I{\omega ^2} + \frac{1}{2}m{v^2} = \hfill \\ \hfill \\ = \frac{1}{2}I{\left( {\frac{v}{R}} \right)^2} + \frac{1}{2}m{v^2} = \hfill \\ \hfill \\ = \frac{1}{2}\left( {\frac{I}{{{R^2}}} + m} \right){v^2} \hfill \\ \end{gathered} \] since, with respect to an inertila system whichis at rest with respect to the road, such wheel has a kinetic energy due to its rotational motion, plus a kinetic energy due to its traslational motion. Here \(R\) is the radius of the wheel
anonymous
  • anonymous
Is my anwer correct? a. 2445.0352 J b. 7335.1056 J c . 221683.1901 J?

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