AmberlyKhan
  • AmberlyKhan
Hallie subtracted a quantity from the polynomial 3y^2 + 8y - 16 and produced the expression (y + 2)(y - 2). What quantity did Hallie subtract? Explain how you got your answer.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
calculusxy
  • calculusxy
I will try to do the work with you... We have the starting polynomial (the one that we will subtract from) to be \(3y^2 + 8y - 16\) and the unknown to be \(x\). The difference will be \((y+2)(y - 2)\). \(3y^2 + 8y - 16 - x = (y + 2)(y - 2)\). I would suggest for you to expand from the factorized form of \((y+ 2)(y - 2)\) by using \(\text {FOIL}\).
calculusxy
  • calculusxy
Make \((y+2)(y-2)\) a polynomial by using FOIL. Do you know how to do that?
AmberlyKhan
  • AmberlyKhan
Yes. After doing that I would set it equal to the one you mentioned, and then I would simplify, right?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

calculusxy
  • calculusxy
If you mean to isolate \(x\) and find the value of it, then yes.
AmberlyKhan
  • AmberlyKhan
Oh yeah, I got it. Thanks! I'll let you know what I got just to make sure.
calculusxy
  • calculusxy
Okay
calculusxy
  • calculusxy
@AmberlyKhan Did you get it?
AmberlyKhan
  • AmberlyKhan
Is it x = 12 + 2y^2 - 8y?
AmberlyKhan
  • AmberlyKhan
And I would factor that?
AmberlyKhan
  • AmberlyKhan
I did something wrong, because the difference I got was y^2 - 28. It shoud be y^2 - 4.
calculusxy
  • calculusxy
Let's check: \((y+2)(y-2) = y^2 - 2y + 2y - 4 = y^2 - 4\) \((3y^2 + 8y - 16) - x = y^2 - 4\) \((3y^2 + 8y - 16) - (3y^2 + 8y - 16) - x = (y^2 - 4) - (3y^2 + 8y - 16)\) \(-x = y^2 - 4 - 3y^2 - 8y + 16\) \(-x = - 2y^2 - 8y + 12\) \(x = 2y^2 + 8y - 12\)
AmberlyKhan
  • AmberlyKhan
How'd you get +16? I got -16.
calculusxy
  • calculusxy
There's an invisible -1 in front of \((3y^2 + 8y - 16)\). So it's basically like you're distributing -1 to -16 to get 16.
AmberlyKhan
  • AmberlyKhan
Oh, nevermind, I got it.
AmberlyKhan
  • AmberlyKhan
You distributed the negative.
calculusxy
  • calculusxy
Yes I distributed the -1
calculusxy
  • calculusxy
Do you understand this now?
AmberlyKhan
  • AmberlyKhan
OK, I got the answer. Thanks for bearing with me!

Looking for something else?

Not the answer you are looking for? Search for more explanations.